Dictionary unpacking in python

For a list, I can split it with one compact line of code:

i_ate = ['apple', 'beetroot', 'cinnamon', 'donut']

# Elaborate
first = i_ate[0]
rest = [item for j, item in enumerate(i_ate) if j != 0]

# Shortcut
first, *rest = i_ate

# Result in both cases:
first # 'apple'
rest # ['beetroot', 'cinnamon', 'donut']

Does someting similar exist for dictionaries?

i_ate = {'apple': 2, 'beetroot': 0, 'cinnamon': 3, 'donut': 8}

# Elaborate
apples = i_ate['apple']
rest = {k: v for k, v in i_ate.items() if k != 'apple'}

# Shortcut??
# -- Your line of code here --

# Result in both cases:
apples # 2
rest # {'beetroot': 0, 'cinnamon': 3, 'donut': 8}

How about unpacking the dict as items? This will work on any python version that supports ordered dicts

>>> _, *rest = i_ate.items()
>>> dict(rest)
{'beetroot': 0, 'cinnamon': 3, 'donut': 8}

As slothrop in the comments suggested, if first_value is also needed, the first item can further be unpacked:

>>> (_, first_val), *rest = i_ate.items()
>>> first_val
2

.items() converts the dictionary into a sequence of tuples

Alternatively, just delete the entry you don't want in-place using del i_ate['apple'] or i_ate.pop('apple').