英文:
Python create diff of two file
问题
data1 = [open("lis1.json", 'r')]
data2 = [open('list2.json', 'r')]
first_set = set(map(tuple, data1))
second_set = set(map(tuple, data2))
x = (first_set - second_set)
print(x)
我正在尝试查看两个列表，并获取列表1中不在列表2中的数据。问题在于列表1的格式对于两组数据都如下：
data1= ["Jane Doe", 98132]["John Doe", 12345]
或
data1=["jane doe",98132]["john doe",12345]data2=["Jane Doe", 98132]["John drew", 8989]["John drew", 8989]["John drew", 8989]data2=["jane doe",98132]["john drew",8989]
我期望的结果是
x = [["John Doe", 12345]
我正在比较用户列表与通话日志，因此可能存在重复。
在文件中，我看到错误消息："Json 标准只允许一个顶级值"。
如果我使用 json(load)：
Traceback (most recent call last):File "/Users/diff.py", line 4, in <module>data1 = json.load(open("list1.json"))File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/json/__init__.py", line 293, in loadreturn loads(fp.read(),File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/json/__init__.py", line 346, in loadsreturn _default_decoder.decode(s)File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/json/decoder.py", line 340, in decoderaise JSONDecodeError("Extra data", s, end)json.decoder.JSONDecodeError: Extra data: line 1 column 19 (char 18)
英文:
data1= [open("lis1.json", 'r')]data2= [open('list2.json', 'r')]first_set = set(map(tuple, data1))second_set = set(map(tuple, data2))x= (first_set-second_set)print(x)
I am attempting to view two list and get the data in list 1 that are not in list two. the issue is list one format for both set of data is as below :
data1= ["Jane Doe", 98132]["John Doe", 12345]
or
data1=["jane doe",98132]["john doe",12345]data2=["Jane Doe", 98132]["John drew", 8989]["John drew", 8989]["John drew", 8989]data2=["jane doe",98132]["john drew",8989]
I was expecting
x = [["John Doe", 12345]
I am comparing a list of users vs call logs so it might have duplicate.
in the file I am seeing this in the errors :"Json standard allows only one top-level value"
if I use json(load)
Traceback (most recent call last):File "/Users/diff.py", line 4, in <module>data1 = json.load(open("list1.json"))File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/json/__init__.py", line 293, in loadreturn loads(fp.read(),File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/json/__init__.py", line 346, in loadsreturn _default_decoder.decode(s)File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/json/decoder.py", line 340, in decoderaise JSONDecodeError("Extra data", s, end)json.decoder.JSONDecodeError: Extra data: line 1 column 19 (char 18)
答案1
得分: 2
你需要使用 json.load() 来解析 JSON。
data1 = json.load(open("list1.json"))data2 = json.load(open("list2.json"))
英文:
You need to use json.load() to parse the JSON.
data1 = json.load(open("list1.json"))data2 = json.load(open("list2.json"))
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