Rust 可以在 O(1) 时间内创建克隆并可以单独更新的集合。

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英文:

Rust sets that can create a clone in O(1) and can be updated separately

问题

我有一组数字,set1 = {1,2,3,4,5},我想在O(1)时间内创建set1的克隆(副本)。
我知道可以使用Rc和Box来实现这一点。
假设这个副本称为set2。

我还想分别更新set1和set2。
例如,

set1.insert(10);
set2.insert(6);

所以最终,我将会有

set1 = {1,2,3,4,5,10}
set2 = {1,2,3,4,5,6}

集合中的元素不会被移除或更新,
我尝试过很多方法,但似乎在某些时候会有一个O(n)的操作来克隆所有元素。

英文:

I have a set of numbers, set1 = {1,2,3,4,5}
and I want to create a clone (copy) of set1 in O(1).
I know I can do this using Rc, Box.
Assume this copy is set2.

I also want to update set1 and set2 separately.
For example

set1.insert(10);
set2.insert(6);

so at the end of the day, I will have

set1 = {1,2,3,4,5,10}
set2 = {1,2,3,4,5,6}

Elements in the set will not be removed or updated,
I've tried a lot of methods, but it seems at some point there will be an O(n) operation that clone all elements.

答案1

得分: 4

为了克隆一个包含n个元素的数据结构,使新的数据结构拥有原始元素的副本,至少需要O(n)的时间复杂度。即使克隆只是复制一块连续的内存块,它仍然是O(n)

由于您的需求不涉及更新“克隆”的数据,您可以使用RcArc来共享它:

use std::{collections::HashSet, hash::Hash, cmp::Eq, rc::Rc};

pub struct PartiallySharedHashSet<T> {
    shared: Rc<HashSet<T>>,
    own: HashSet<T>,
}

impl<T: Hash + Eq> PartiallySharedHashSet<T> {
    pub fn new(shared: Rc<HashSet<T>>) -> Self {
        Self {
            shared,
            own: HashSet::new()
        }
    }

    pub fn insert(&mut self, item: T) -> bool {
        if self.shared.contains(&item) {
            false
        } else {
            self.own.insert(item)
        }
    }

    pub fn contains(&self, item: &T) -> bool {
        self.own.contains(item) || self.shared.contains(item)
    }
}

用法:

fn main() {
    let mut set = HashSet::new();
    set.insert(1);
    let set = Rc::new(set);

    let mut set1 = PartiallySharedHashSet::new(set.clone());
    set1.insert(2);
    let mut set2 = PartiallySharedHashSet::new(set);
    set2.insert(3);

    assert!(set1.contains(&1));
    assert!(set1.contains(&2));
    assert!(!set1.contains(&3));

    assert!(set2.contains(&1));
    assert!(!set2.contains(&2));
    assert!(set2.contains(&3));
}
英文:

To clone a data structure containing n elements so that the new structure has its own copy of the original elements must take at least O(n) time complexity. Even if cloning is just copying a contiguous block of memory, it's fast but it's still O(n).

Since your requirement doesn't involve updating the "cloned" data, you can instead share it using Rc or Arc:

use std::{collections::HashSet, hash::Hash, cmp::Eq, rc::Rc};

pub struct PartiallySharedHashSet&lt;T&gt; {
    shared: Rc&lt;HashSet&lt;T&gt;&gt;,
    own: HashSet&lt;T&gt;,
}

impl&lt;T: Hash + Eq&gt; PartiallySharedHashSet&lt;T&gt; {
    pub fn new(shared: Rc&lt;HashSet&lt;T&gt;&gt;) -&gt; Self {
        Self {
            shared,
            own: HashSet::new()
        }
    }

    pub fn insert(&amp;mut self, item: T) -&gt; bool {
        if self.shared.contains(&amp;item) {
            false
        } else {
            self.own.insert(item)
        }
    }

    pub fn contains(&amp;self, item: &amp;T) -&gt; bool {
        self.own.contains(item) || self.shared.contains(item)
    }
}

Usage:

fn main() {
    let mut set = HashSet::new();
    set.insert(1);
    let set = Rc::new(set);

    let mut set1 = PartiallySharedHashSet::new(set.clone());
    set1.insert(2);
    let mut set2 = PartiallySharedHashSet::new(set);
    set2.insert(3);

    assert!(set1.contains(&amp;1));
    assert!(set1.contains(&amp;2));
    assert!(!set1.contains(&amp;3));

    assert!(set2.contains(&amp;1));
    assert!(!set2.contains(&amp;2));
    assert!(set2.contains(&amp;3));
}

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  • 本文由 发表于 2023年4月7日 05:12:33
  • 转载请务必保留本文链接:https://go.coder-hub.com/75953825.html
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