英文:
How to check if a date is still less than 5 days in django query?
问题
我尝试检查订单创建日期是否仍然少于5天，然后我想显示一个新订单文本。
这是我尝试实现这一点的方式：
def vendor_orders(request):five_days = datetime.now() + timedelta(days=5)new_orders = CartOrder.objects.filter(payment_status="paid", date__lte=five_days).order_by("-id")
这会返回数据库中所有日期少于5天的订单，这意味着所有订单，包括旧订单和新订单，都会被返回，这不是我期望的结果。如果我手动创建一个订单并将日期手动设置为未来的某个日期，比如七月或八月，它不会返回该订单。
请问我该如何处理这个逻辑？我想要的只是如果订单创建日期还没有超过5天，就将其显示为新订单。
模板更新：
我想要检查订单是否是新订单，然后显示一个新徽章。
Views.py：
@login_requireddef vendor_orders(request):five_days = datetime.now() - timedelta(days=5) # 这是5天前new_order = CartOrder.objects.filter(payment_status="paid", vendor=request.user.vendor, date__gte=five_days).order_by("-id")order = CartOrder.objects.filter(payment_status="paid", vendor=request.user.vendor).order_by("-id")context = {"order": order,"five_days": five_days,"new_order": new_order,}return render(request, "vendor/vendor-order.html", context)
{% for o in order %}<tr><th scope="row">#{{o.oid}} <span class="badge">{% if o.date > five_days %}New{% endif %}</span></th><th scope="row"><a href="{% url 'vendor:order-detail' o.oid %}" class="btn btn-primary">View Order</a></th><td>{{o.date}}</td></tr>{% endfor %}
英文:
I am trying to check if the date an order was created is still less than 5 days, then i want to display a New Order Text.
This is how i have tried doing this
def vendor_orders(request):five_days = datetime.now() + timedelta(days=5)new_orders = CartOrder.objects.filter(payment_status="paid", date__lte=five_days).order_by("-id")
This is returning all the orders in the database that the date is less than 5 days, which means all orders both old and new are being returned and this is not what i am expecting.
If i manually create an order and set the date manually to some date in the future e.g July or August, it does not return that order.
Please how can i go about this logic? all i want to do is display an order as new orders if the date which the order was created is not yet older than 5 days.
Template Update
i want to check if the order is a new order then i display a new badge
Views.py
@login_requireddef vendor_orders(request):five_days = datetime.now() - timedelta(days=5) # this is 5 days agonew_order = CartOrder.objects.filter(payment_status="paid", vendor=request.user.vendor, date__gte=five_days).order_by("-id")order = CartOrder.objects.filter(payment_status="paid", vendor=request.user.vendor).order_by("-id")context = {"order":order,"five_days":five_days,"new_order":new_order,}return render(request, "vendor/vendor-order.html", context)
{% for o in order %}<tr><th scope="row">#{{o.oid}} <span class="badge">{% if o.date > five_days %}New{% endif %}</span></th><th scope="row"><a href="{% url 'vendor:order-detail' o.oid %}" class="btn btn-primary">View Order</a></th><td>{{o.date}}</td></tr>{% endfor %}
答案1
得分: 1
如果我理解正确，我认为这是你想要的。
def vendor_orders(request):five_days = datetime.now() - timedelta(days=5) #5天前的日期#日期大于5天前的订单new_orders = CartOrder.objects.filter(payment_status="paid", date__gte=five_days).order_by("-id")
英文:
If I understand correctly, I think this is what you want.
def vendor_orders(request):five_days = datetime.now() - timedelta(days=5) #5 days ago#orders with a date greater than the date 5 days agonew_orders = CartOrder.objects.filter(payment_status="paid", date__gte=five_days).order_by("-id")
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