Regex: The word must have an apostrophe at the beginning and at the end ("word")

I currently have the following program that uses a regular expression:

const regex = /[\s]|('[^']')|[\w-]+|[']/gm;

When running:

console.log("'one 'two' three'".match(regex) || []);

I get:

[
    "'",
    "one",
    " ",
    "'",
    "two",
    "'",
    " ",
    "three",
    "'"
]

I need to update the regular expression in a way that I can get at the end:

[
    "'",
    "one",
    " ",
    "'two'",
    " ",
    "three",
    "'"
]

You missed + inside your quoted pattern.

\s|('[\w-]+')|[\w-]+|'

console.log("'one 'two' three'".match(/\s|('[\w-]+')|[\w-]+|'/gm) || []);
// Array(7) [ "'", "one", " ", "'two'", " ", "three", "'" ]

Also I've changed it to match only word symbols and minuses (by analogy with next pattern), to exclude matching of 'one '.

If matching of phrases in quotes (like 'abc abc') is expected you could you could use \s|('(?=[\S])[^']+?(?<=[\S])')|[\w-]+|'

EDIT: according to corrected input by OP, to allow words containing ', like that's:

\s|((?<=[\s|^])'[\w-][\w'-]*[\w-]'(?=\s|$))|[\w-][\w'-]*[\w-]|'|\w