英文:
Grafana label_values regex to capture uri without query parameter
问题
label_values(http_client_requests_seconds_count, uri)
英文:
I've created a repeating panel per API that my application calls, showing the http status returned.
The query that I could write for the variable so far is:
label_values(http_client_requests_seconds_count, uri)
And the selector is populated with URIs like:
/user/accounts
/user/contact_info
/account/details?accnr=1234
/account/details?accnr=5678
How should the query look like in order to omit the query parameter and get the result as:
/user/accounts
/user/contact_info
/account/details
答案1
得分: 1
我明白你的请求。以下是翻译好的部分：
你应该使用 Regex: (.*?)(\?.*)?（位于查询右下方的字段）
它将从你的数值中移除 ? 和后面的所有内容，并在此之后应用不同的方法。
你无法通过查询来实现这一点，主要是因为即使 label_values 严格来说不是 Prometheus 查询的一部分。label_values 是 Grafana 用于从 Prometheus（以及类似的系统）指标中提取标签的函数。
英文:
You should use Regex: (.*?)(\?.*)? (field located right under Query)
It will remove ? and everything what follows it from your values. And also applies distinct after it.
You can't do this through query, mostly because even label_values is not part of query to Prometheus strictly speaking. label_values is Grafana's function for extraction of labels from Prometheus' (and alike) metrics.
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