Cannot compute profit and loss, program stops with no output

Question:
> If cost price and selling price of an item is input through the keyboard, write a program to determine whether the seller has made profit or incurred loss. Also determine how much profit he made or loss incurred.

Here is my code:

#include <stdio.h>

int main() {
    int x, y, z, b, n;
    char k = '%';
    char r = '$';
    printf("Enter cost of item:-");
    scanf("%d", &x);
    printf("Enter selling price of item:-");
    scanf("%d", &y);
    if (x < y) {
    	n = y - x;
    	z = 100 / x;
    	b = n / z;
    	printf("You made %d%c profit \n", b, k);
    	printf("or\n");
    	printf("%d %c profits\n", n, r);
    }
    if (x > y) {
    	n = y - x;
    	z = 100 / x;
    	b = n / z;
    	printf("You made %d%c loss \n", b, k);
    	printf("or\n");
    	printf("%d %c loss\n", n, r);
    }
  	return 0;
}

Hey I'm new in C programming knows basic only. Today I'm learning if / else and I try to solve this question.
But my code not giving any error and warning. It takes input and after its end my if not working.
please Help:(

There is a problem here:

    z = 100 / x;
    b = n / z;

If the price x is larger than 100, z will have the value 0 because of integer division semantics and n / z will cause undefined behavior because of division overflow, which may cause the program to stop.

Here are my recommendations:

• avoid dividing by zero
• use floating point arithmetics to avoid excessive rounding.
• use explicit names to make your program easier to read and understand.
• test the return value of scanf() to detect invalid or missing input.

Here is a modified version:

#include <stdio.h>

int main(void) {
    int cost, sale;

    printf("Enter cost of item: ");
    if (scanf("%d", &cost) != 1) {
        printf("input error!\n");
        return 1;
    }
    printf("Enter selling price of item: ");
    if (scanf("%d", &sale) != 1) {
        printf("input error!\n");
        return 1;
    }
    if (cost == 0) {
        printf("no cost base, total profit of $%d\n", sale);
    } else
    if (cost == sale) {
        printf("it's a wash: no profit, no loss\n");
    } else
    if (cost < sale) {
        int profit = sale - cost;
        int margin = profit * 100 / cost;
        printf("You made a %d%% profit of $%d\n", margin, profit);
    } else {
        int loss = cost - sale;
        int margin = loss * 100 / cost;
        printf("You made a %d%% loss of $%d\n", margin, loss);
    }
    return 0;
}

Here. is the complete answer. for you. have have make mistake in calculation

#include <stdio.h>

int main() {
    float x, y, z, b, n;
    char k = '%';
    char r = '$';
    printf("Enter cost of item: ");
    scanf("%f", &x);
    printf("Enter selling price of item: ");
    scanf("%f", &y);
    if (x <= y) {
        n = y - x;
        z = n/x*100;
      
        printf("You made %f %c profit \n", z, k);
        printf("or\n");
        printf("%f %c profits\n", n, r);
    }
    if (x > y) {
        n = x-y;
        z = n/x*100;
        printf("You made %f%c loss \n", z, k);
        printf("or\n");
        printf("%f %c loss\n", n, r);
    }
    return 0;
}