添加一个基于工作日的工作时间。

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英文:

Add a working hours based on business days

问题

需要为指定日期添加工作小时,以及根据工作日添加日期。

示例:

DECLARE @Date datetime = '2023-04-07 23:15:50.720';
DECLARE @AddHours int = 3;

如果DATEADD(HOUR, @AddHours, @Date) 落在 '星期六' 或 '星期天',我们需要将它添加到下一个工作日,即从星期一到星期五,基于 @AddHours 输入。

我尝试了下面的代码,但它不会计算周末:

SELECT DATEADD(HOUR, @AddHours, @Date)

示例:

DECLARE @Date datetime = '2023-04-07 23:15:50.720';
DECLARE @AddHours int = 3;

根据上述 @AddHours,输出应该是:

"2023-04-10 02:15:50.720"

请为我提供一个解决方案,因为我是前端开发人员。

英文:

I need to add a working hours for a given date and need to add dates based on working days.

Example:

DECLARE @Date datetime  = '2023-04-07 23:15:50.720';
DECLARE @AddHours int = 3;

IF the DATEADD(HOUR, @AddHours, @Date) falls under 'Saturday' or 'Sunday' we need to add it to next Working days between Monday to Friday based on @AddHours input

I tried with below code but it will not calculate for weekends

SELECT DATEADD(HOUR, @AddHours, @Date)

Example:

DECLARE @Date datetime  = '2023-04-07 23:15:50.720';
DECLARE @AddHours int = 3;

As per above @AddHours, the output supposed to be :

"2023-04-10 02:15:50.720"

Please provide me a solution as I'm a front end developer

答案1

得分: 0

你可以使用DATENAMEDATEPART来获取你的新日期是星期日还是星期六,并根据这一情况调整添加的值:

Declare @Date datetime  = '2023-04-07 23:15:50.720'

Declare @AddHours int = 3

SELECT CASE 
			WHEN DATENAME(WEEKDAY, DATEADD(HOUR, @AddHours, @Date)) = 'Saturday' THEN DATEADD(HOUR, @AddHours + 48, @Date)
			WHEN DATENAME(WEEKDAY, DATEADD(HOUR, @AddHours, @Date)) = 'Sunday' THEN DATEADD(HOUR, @AddHours + 24, @Date)
		    ELSE DATEADD(HOUR, @AddHours, @Date)
	   END

在T-SQL中,你可以使用case when块或IIF来创建条件。

英文:

You can use DATENAME or DATEPART to get if your new date is Sunday or Saturday, and adjust the adding value depending on it:

Declare @Date datetime  = '2023-04-07 23:15:50.720'

Declare @AddHours int = 3

SELECT CASE 
			WHEN DATENAME(WEEKDAY, DATEADD(HOUR, @AddHours, @Date)) = 'Saturday' THEN DATEADD(HOUR, @AddHours + 48, @Date)
			WHEN DATENAME(WEEKDAY, DATEADD(HOUR, @AddHours, @Date)) = 'Sunday' THEN DATEADD(HOUR, @AddHours + 24, @Date)
		    ELSE DATEADD(HOUR, @AddHours, @Date)
	   END

In the T-SQL you can create conditions using the case when block or IIF.

huangapple
  • 本文由 发表于 2023年4月4日 16:03:01
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