英文:
How to access local variable inside the block if there is a block level variable with the same name in c++?
问题
要访问块内的局部变量，如果存在与同名的块级变量。
英文:
#include <iostream>
using namespace std;
int main() {
int a = 20; // want to access this variable
{
int a = 30;
cout << a << endl;
}
return 0;
}
I want to access the local variable inside the block if there is a block-level variable with the same name
答案1
得分: 1
无法访问内部作用域中被相同名称隐藏的块作用域名称。如果您希望从外部块作用域访问 a，则必须删除内部作用域中的 a 声明。
从技术上讲，您可以使用任何间接方式访问命名对象，例如使用引用：
int a = 20;
int& ref = a;
{
int a = 30;
std::cout << ref << '\n';
}
但我不建议使用这种解决方案。相反，我建议为每个变量提供一个唯一的名称：
int meaningful_name = 20;
{
int clearly_a_different_variable = 30;
std::cout << meaningful_name << '\n';
}
英文:
You cannot access block scope names hidden by the same name in an inner scope. If you wish to access a from the outer block scope, then you must remove the declaration of the a in the inner scope.
Technically, you can access the named object using any form of indirection, for example using a reference:
int a = 20;
int& ref = a;
{
int a = 30;
std::cout << ref << '\n';
}
But, I wouldn't recommend this solution. Instead, I recommend giving a unique name for each variable:
int meaningful_name = 20;
{
int clearly_a_different_variable = 30;
std::cout << meaningful_name << '\n';
}
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