linux merge rows if Columns less than X

I need you support in creating the output.
I have output as

1  ABC  STATUS   	 
   7   	PROHIBITED   
   8   	PROHIBITED   
2  CDE  STATUS   	 
   7    PROHIBITED   
   8    PROHIBITED   
3  FGH  STATUS   	 
   142  PROHIBITED   
2  HIJ  STATUS   	 
   7   	PROHIBITED   

I am trying to achieve as

`1  ABC  STATUS   	 7   	PROHIBITED   8   	PROHIBITED   
2  CDE  STATUS   	 7    PROHIBITED   8    PROHIBITED   
3  FGH  STATUS   	 142  PROHIBITED   
2  HIJ  STATUS   	 7   	PROHIBITED

OR Either below where every first and second column is filled in below empty gaps.

`1  ABC  STATUS   	 
1  ABC   7   	PROHIBITED   
1  ABC   8   	PROHIBITED   
2  CDE  STATUS   	 
2  CDE   7    PROHIBITED   
2  CDE  8    PROHIBITED   
3  FGH  STATUS   	 
3  FGH   142  PROHIBITED   
2  HIJ  STATUS   	 
2  HIJ    7   	PROHIBITED   
2  HIJ    8   	PROHIBITED   `

so far I have tried to achieve this in one single row with

cat file | paste -sd'\t\n'

but it is not showing the result as expected. it would be appreciated if any one can provide me with guidance as to how to achieve

One awk idea for generating the first set of output:

awk '
    { if (NF==3)
         printf "%s%s",(NR>1 ? "\n" : ""),$0        # if not 1st row of input then prefix the output with "\n" (to terminate previous line of output)
      else      
         printf "%s",$0
    }
END {print ""}                                      # terminate last line of output
' file

This generates:

1  ABC  STATUS   7    PROHIBITED   8    PROHIBITED
2  CDE  STATUS   7    PROHIBITED   8    PROHIBITED
3  FGH  STATUS   142  PROHIBITED
2  HIJ  STATUS   7    PROHIBITED   8    PROHIBITED

Using any POSIX awk you can just test if a line starts with a space or not:

$ awk '{printf "%s%s", (/^[[:space:]]/ ? "" : sep), $0; sep=ORS} END{print ""}' file
1  ABC  STATUS          7    PROHIBITED      8    PROHIBITED
2  CDE  STATUS          7    PROHIBITED      8    PROHIBITED
3  FGH  STATUS          142  PROHIBITED
2  HIJ  STATUS          7    PROHIBITED

With your shown samples and attempts please try following GNU awk code.

awk -v RS='(^|\n)[0-9]+' -v OFS="\t" '
RT && FNR>1{
  gsub(/\n/,"")
  $1=$1
  print
}
END{
  if($0){
    gsub(/^ +|\n/,"")
    $1=$1
    print
  }
}
'   Input_file

If lines to be joined always begin with blanks as in the sample input, then a sed solution could be

sed -e :a -e '$!N;s/\n\([[:blank:]]\)//;ta' -e 'P;D' file

This might work for you (GNU sed):

sed '/^\S/{:a;x;s/\n//gp;d};H;$!d;ba' file

Store records in the hold space and at the start of a new record or the end of the file, swap back to the hold space, remove any newlines and print.

N.B. A new record is designated by a non-white space character at the start of a line.