英文:
golang illegal base64 data at input byte
问题
Python
import base64
print(base64.b64decode('//Py+vX7suTx8A=='))
Go
package main
import (
"encoding/base64"
"fmt"
)
func main() {
data, err := base64.RawStdEncoding.DecodeString("//Py+vX7suTx8A==")
fmt.Println(err)
}
为什么 Python 可以解码这个字符串，而 Go 却失败了？
英文:
Python
>>> print(base64.b64decode('//Py+vX7suTx8A=='))
b'\xff\xf3\xf2\xfa\xf5\xfb\xb2\xe4\xf1\xf0'
Go
>>> data, err := base64.RawStdEncoding.DecodeString("//Py+vX7suTx8A==")
err -> illegal base64 data at input byte 14
Why can Python decode this string while Go fails?
答案1
得分: 2
RawStdEncoding，顾名思义，接受“原始”的base64编码字符串。而你使用的字符串则使用了2个“=”进行填充。尝试移除它们，你应该就不会出现错误了：
data, err := base64.RawStdEncoding.DecodeString("//Py+vX7suTx8A") // 没有填充
if err != nil {
fmt.Printf("err: %v\n", err)
}
fmt.Printf("data: %v\n", data)
正如@JimB所说，如果你仍然想解码填充的字符串，只需使用带填充版本的base64.StdEncoding。
data, err := base64.StdEncoding.DecodeString("//Py+vX7suTx8A==")
if err != nil {
fmt.Printf("err: %v\n", err)
}
fmt.Printf("data: %v\n", data)
英文:
RawStdEncoding, as its name suggests, accepts "raw" base64 encoded strings. The string you used on the other hand is padded with 2 "="s. try removing them and you should get no errors:
data, err := base64.RawStdEncoding.DecodeString("//Py+vX7suTx8A") // no paddings
if err != nil {
fmt.Printf("err: %v\n", err)
}
fmt.Printf("data: %v\n", data)
And as @JimB said, if you want to decode padded strings anyway, just use base64.StdEncoding with the padded version.
data, err := base64.StdEncoding.DecodeString("//Py+vX7suTx8A==")
if err != nil {
fmt.Printf("err: %v\n", err)
}
fmt.Printf("data: %v\n", data)
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