R函数切换列名

huangapple
go评论92阅读模式
英文:

R function to switch column names

问题

reproducible minimal example dataset

  1. pid<-1:30
  2. y1<-rnorm(30,10,10)
  3. y2<-rnorm(30,10,10)
  4. x1<-rnorm(30,5,2)
  5. x2<-rnorm(30,5,2)
  7. data<-data.frame(pid,y1,y2,x1,x2)

This is small reproducible example, but I have more variables such as I1, I2, etc...

I am trying to make a function that can switch the function name so that 'y1' become 'y2'
and 'y2' become 'y1'
'x1' become 'x2' and 'x2' become 'x1'

  2. rename<-function(data=data,
  3.                  
  4.                  dv=y,
  5.                  IV=x,
  6.                  number_of_IV=1){
  8.    
  9. rename_with(
  10.   data,
  11.   .fn=~gsub(
  12.     pattern='1^',
  13.     replacement='2',
  14.     .x
  15.   ),
  16.   .cols=matches('^y'|'^x')
  17. )
  18.   
  19. rename_with(
  20.   data,
  21.   .fn=~gsub(
  22.     pattern='2^',
  23.     replacement='1',
  24.     .x
  25.   )
  26.   .cols=matches('^y'|'^x')
  27.   )
  28. )
  29.  
  30. }

However, it does not work.

  2. trouble shooting the fuction that I wrote, so that I can use that function.
英文:

reproducible minimal example dataset

  1. pid&lt;-1:30
  2. y1&lt;-rnorm(30,10,10)
  3. y2&lt;-rnorm(30,10,10)
  4. x1&lt;-rnorm(30,5,2)
  5. x2&lt;-rnorm(30,5,2)
  7. data&lt;-data.frame(pid,y1,y2,x1,x2)

This is small reproducible example, but I have more variables such as I1, I2, etc...

I am trying to make a function that can switch the function name so that 'y1' become 'y2'
and 'y2'become 'y1'
'x1' become 'x2' and 'x2' become 'x1'

  2. rename&lt;-function(data=data,
  3.                  
  4.                  dv=y,
  5.                  IV=x,
  6.                  number_of_IV=1){
  8.    
  9. rename_with(
  10.   data,
  11.   .fn=~gsub(
  12.     pattern=&#39;1^&#39;,
  13.     replacement=&#39;2&#39;,
  14.     .x
  15.   ),
  16.   .cols=matches(&#39;^y&#39;|&#39;^x&#39;)
  17. )
  18.   
  19. rename_with(
  20.   data,
  21.   .fn=~gsub(
  22.     pattern=&#39;2^&#39;,
  23.     replacement=&#39;1&#39;,
  24.     .x
  25.   )
  26.   .cols=matches(&#39;^y&#39;|&#39;^x&#39;)
  27.   )
  28. )
  29.  
  30. }

However, it does not work.

  2. trouble shooting the fuction that I wrote, so that I can use that function.

答案1

得分: 1

以下是翻译好的部分：

为什么你想要这个？似乎是一个 xy问题

无论如何，以下是一种方法来实现它

  1. head(data)
  2.   pid       x1        y1       x2         y2
  3. 1   1 5.087567  4.424669 6.830336 11.6921347
  4. 2   2 4.386710 21.870220 1.898388 21.0484717
  5. 3   3 5.154918  4.103774 7.926982  4.3101622
  6. 4   4 2.528215  3.572182 5.407407  8.3941766
  7. 5   5 6.003412 13.877344 6.188354  0.1214239
  8. 6   6 8.527333  6.971523 4.559890  7.3657691
  10. head(data) %>%
  11.    rename_with(~str_replace_all(.,&quot;\\d$&quot;, ~abs(2-as.numeric(.))+1))
  13.   pid       x2        y2       x1         y1
  14. 1   1 5.087567  4.424669 6.830336 11.6921347
  15. 2   2 4.386710 21.870220 1.898388 21.0484717
  16. 3   3 5.154918  4.103774 7.926982  4.3101622
  17. 4   4 2.528215  3.572182 5.407407  8.3941766
  18. 5   5 6.003412 13.877344 6.188354  0.1214239
  19. 6   6 8.527333  6.971523 4.559890  7.3657691
英文:

Why would you want this? Seems like an xy problem

Anyway here is one way to do it

  1. head(data)
  2.   pid       x1        y1       x2         y2
  3. 1   1 5.087567  4.424669 6.830336 11.6921347
  4. 2   2 4.386710 21.870220 1.898388 21.0484717
  5. 3   3 5.154918  4.103774 7.926982  4.3101622
  6. 4   4 2.528215  3.572182 5.407407  8.3941766
  7. 5   5 6.003412 13.877344 6.188354  0.1214239
  8. 6   6 8.527333  6.971523 4.559890  7.3657691
  10. head(data) %&gt;%
  11.    rename_with(~str_replace_all(.,&quot;\\d$&quot;, ~abs(2-as.numeric(.))+1))
  13.   pid       x2        y2       x1         y1
  14. 1   1 5.087567  4.424669 6.830336 11.6921347
  15. 2   2 4.386710 21.870220 1.898388 21.0484717
  16. 3   3 5.154918  4.103774 7.926982  4.3101622
  17. 4   4 2.528215  3.572182 5.407407  8.3941766
  18. 5   5 6.003412 13.877344 6.188354  0.1214239
  19. 6   6 8.527333  6.971523 4.559890  7.3657691

答案2

得分: 0

你可以使用 chartr 将 1 更改为 2，将 2 更改为 1。

  1. head(data, 2)
  2. #  pid       y1        y2       x1       x2
  3. #1   1 31.54238 -3.972442 5.178496 4.370217
  4. #2   2 22.21881 11.122397 4.384974 4.177646
  6. names(data) <- chartr("12", "21", names(data))
  8. head(data, 2)
  9. #  pid       y2        y1       x2       x1
  10. #1   1 31.54238 -3.972442 5.178496 4.370217
  11. #2   2 22.21881 11.122397 4.384974 4.177646
英文:

You can use chartr to change 1 to 2 and 2 to 1.

  1. head(data, 2)
  2. #  pid       y1        y2       x1       x2
  3. #1   1 31.54238 -3.972442 5.178496 4.370217
  4. #2   2 22.21881 11.122397 4.384974 4.177646
  6. names(data) &lt;- chartr(&quot;12&quot;, &quot;21&quot;, names(data))
  8. head(data, 2)
  9. #  pid       y2        y1       x2       x1
  10. #1   1 31.54238 -3.972442 5.178496 4.370217
  11. #2   2 22.21881 11.122397 4.384974 4.177646
  14. </details>

huangapple
  • 本文由 发表于 2023年4月1日 00:06:18
  • 转载请务必保留本文链接：https://go.coder-hub.com/75900614.html
  • function
  • r
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定