Scale ticks/ breaks to percentile in continuous colourbar in scale_fill_gradientn (ggplot2)

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英文:

Scale ticks/ breaks to percentile in continuous colourbar in scale_fill_gradientn (ggplot2)

问题

这是我使用ggplot制作的可重现的代码,生成了类似的图形:

set.seed(123)
library(ggplot2)
df = data.frame(
	"x_var" = factor(rep(letters[1:10], 100)),
	"y_var" = factor(rep(LETTERS[1:10], each=100)),
	"fill_var" = sample(c(rexp(200, rate = 100),rexp(600, rate = 10), rexp(100, rate = 1), rexp(100, rate = 0.01)))
)

fill_colours = c("chartreuse4", "chartreuse3", "darkolivegreen2",
                 "khaki", "gold", "darkorange", "firebrick", "darkred")
fill_values_quantiles = seq(from = 0.05,
                            to = 0.95,
                            length.out = length(fill_colours) - 2)

ggplot(data = df, aes(x = x_var, y = y_var, fill = fill_var)) +
	geom_tile() +
	scale_fill_gradientn(
		colours = fill_colours,
		values = c(0,
							 quantile(df$fill_var, fill_values_quantiles),
							 ceiling(max(df$fill_var)))
		)

这个代码生成了与您提供的图形相似的图。

您想要的图例条是使用scale_fill_gradientn函数的参数values来控制的。要获得与您提供的示例图例相似的效果,您可以按照以下方式修改values参数:

values = c(0, quantile(df$fill_var, fill_values_quantiles), ceiling(max(df$fill_var))

这将在图例中创建与数据中的值对应的标记,这些值由values参数定义,它们将均匀分布在颜色条上。这将为您提供一个类似于您示例中的图例的连续颜色条。

如果您不想使用分位数,而是想使用某种转换,例如对数转换,您可以使用trans参数来指定转换函数。在这种情况下,您需要确保图例上的标记显示原始值而不是转换后的值。

英文:

Here's a reproducible code of the type of plot that I have with ggplot:

set.seed(123)
library(ggplot2)
df = data.frame(
	"x_var" = factor(rep(letters[1:10], 100)),
	"y_var" = factor(rep(LETTERS[1:10], each=100)),
	"fill_var" = sample(c(rexp(200, rate = 100),rexp(600, rate = 10), rexp(100, rate = 1), rexp(100, rate = 0.01)))
)

fill_colours = c("chartreuse4", "chartreuse3", "darkolivegreen2",
                 "khaki", "gold", "darkorange", "firebrick", "darkred")
fill_values_quantiles = seq(from = 0.05,
                            to = 0.95,
                            length.out = length(fill_colours) - 2)

ggplot(data = df, aes(x = x_var, y = y_var, fill = fill_var)) +
	geom_tile() +
	scale_fill_gradientn(
		colours = fill_colours,
		values = c(0,
							 quantile(df$fill_var, fill_values_quantiles),
							 ceiling(max(df$fill_var)))
		)

This gives this figure:

Scale ticks/ breaks to percentile in continuous colourbar in scale_fill_gradientn (ggplot2)

How do I get the legend bar like this?

Scale ticks/ breaks to percentile in continuous colourbar in scale_fill_gradientn (ggplot2)

I did this plot with this colour gradient because using quantiles to highlight the differences in the tile plots fits what I want to show. This plot will be done many times, with different dataframes.

I want the legend like the example I put above so that we can have a better idea of what's going on for the green values. With words, I want the ticks that correspond to the values I have put in the argument values of scale_fill_gradientn, and I want them to be evenly spaced. I still want a continuous colorbar.

Another idea instead of using quantiles: I could also probably work with a transformation of some sort, e.g. a log transformation, but in that case I'd want the real values of fill_val printed in the legend text at the ticks, and not the transformed values. But I'd like the other possibility better.

答案1

得分: 1

我想知道你是否想记录颜色比例尺?因为你有很少的大数值:

ggplot(data = df, aes(x = x_var, y = y_var, fill = fill_var)) +
  geom_tile() +
  scale_fill_gradientn(colours = fill_colours,
                        trans="log10",
                        breaks=trans_breaks('log10', function(x) 10^x),
                        labels=trans_format('log10', function(x) round(10^x, 2)))

[![enter image description here][1]][1]


<details>
<summary>英文:</summary>

I wonder if you want to log teh color scale? since you have very few large values:

    ggplot(data = df, aes(x = x_var, y = y_var, fill = fill_var)) +
      geom_tile() +
   
      scale_fill_gradientn(colours = fill_colours,
                            trans=&quot;log10&quot;,
                            breaks=trans_breaks(&#39;log10&#39;, function(x) 10^x),
                            labels=trans_format(&#39;log10&#39;, function(x) round(10^x,2)))

[![enter image description here][1]][1]


  [1]: https://i.stack.imgur.com/sqQit.png

</details>



# 答案2
**得分**: 1

你已经非常接近了。你的问题基本上是“如何将我的填充向量转换为百分位数”。为此,你可以使用 `ecdf` 函数。代码中的其他注释。

```r
## 稍作更改以包括0和1
fill_values_quantiles <- seq(0, 1, length.out = length(fill_colours))
## 使用这个向量来表示标签的分位数断点(!)
quants <- quantile(df$fill_var, fill_values_quantiles)
## 将填充中的每个值转换为分位数
df$ptile_var <- ecdf(df$fill_var)(df$fill_var)

## 使用分位数来填充
ggplot(data = df, aes(x = x_var, y = y_var, fill = ptile_var)) +
  geom_tile() +
  scale_fill_gradientn(
    ## 使用上面的向量来设置断点和标签
    colours = fill_colours,
    breaks = fill_values_quantiles,
    labels = round(quants, 3)
  )

Scale ticks/ breaks to percentile in continuous colourbar in scale_fill_gradientn (ggplot2)

英文:

You're very close. Your question is basically "how to convert my fill vector into percentiles". For this you can use the ecdf function. Other comments in the code.

## slightly changed to include 0 and 1
fill_values_quantiles &lt;- seq(0, 1, length.out = length(fill_colours))
## use this for a vector of your quantile breaks for the labels (!)
quants &lt;- quantile(df$fill_var, fill_values_quantiles)
## convert every value in your fill to quantiles
df$ptile_var &lt;- ecdf(df$fill_var)(df$fill_var)

## use the percentiles for fill
ggplot(data = df, aes(x = x_var, y = y_var, fill = ptile_var)) +
  geom_tile() +
  scale_fill_gradientn(
## use your vectors from above for breaks and labels 
    colours = fill_colours,
    breaks = fill_values_quantiles,
    labels = round(quants, 3)
  )

Scale ticks/ breaks to percentile in continuous colourbar in scale_fill_gradientn (ggplot2)<!-- -->

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  • 本文由 发表于 2023年3月31日 22:56:02
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