英文:
How to write regular expression to find exact word at 10th position in Javascript adobe?
问题
I want to get result as CON from above line in adobe classification rule builder code which i have been using to get the desired output is
我想从上述行中获取CON作为结果，我一直在使用的Adobe分类规则生成器代码来获取所需的输出是
^(.+?)_(.+?)_(.+?)_(.+?)_(.+?)_(.+?)_(.+?)_(.+?)_(.+?)_(.+?)_(.+?)$
however this code only give output as any word which is at 10th position? I want to get output which matches CON and is at 10th position.
但是，这段代码只会输出位于第10个位置的任何单词？我想要获取匹配CON并且位于第10个位置的输出。
英文:
I have been trying to write regular expression which find a specific word at specific position in javascript adobe classification rule builder
DI_NEO_OP_BRA_CRC_LRN_DIS_EP_NA_CON_UC_NA
I want to get result as CON from above line in adobe classification rule builder code which i have been using to get the desired output is
^(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)\_(.+?)$
however this code only give output as any word which is at 10th position? I want to get output which matches CON and is at 10th position.
答案1
得分: 1
可以使用一个捕获组，然后匹配"CON"后面要么是下划线（"_"）要么是字符串结尾：
^(?:[^_\n]*_){9}(CON)(?:_|$)
解释
^字符串的开始(?:[^_\n]*_){9}重复9次，匹配除了下划线（""）和换行符之外的任何字符，然后匹配下划线（""）(CON)捕获组1，匹配"CON"(?:_|$)匹配下划线（"_"）或者断言字符串的结尾
英文:
You can use a single capture group, and then match CON followed by either _ or the end of the string:
^(?:[^_\n]*_){9}(CON)(?:_|$)
Explanation
^Start of string(?:[^_\n]*_){9}Repeat 9 times matching any character except_or a newline, and then match_(CON)Capture group 1, match CON(?:_|$)Match either_or assert the end of the string
答案2
得分: 0
(?<= # 匹配后
^ # 行的开始，然后
(?:[^_]+_) # 1+ 个非下划线字符后跟 '_',
{9} # 9 次
) #
CON # 字面上的 'CON',
(?=_|$) # 后面跟 '_'' 或行的结束。
英文:
(?<= # Match after
^ # the beginning of the line, then
(?:[^_]+_) # 1+ non-underscore chars followed by '_',
{9} # 9 times
) #
CON # literal 'CON',
(?=_|$) # followed by '_' or end of line.
Try it on regex101.com.
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