Teradata按ID和日期进行案例条件检查

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英文:

Teradata Case condition check by ID and Date

问题

以下是翻译好的部分:

"有多条记录中有相同的ID,但具有不同的startdate和enddate时间跨度。

我需要编写一个Teradata SQL条件来按ID检查,并且其开始日期是当前月份,然后与上一条记录的enddate进行比较。

条件如下:
我需要编写一个Teradata SQL条件来按ID检查,其开始日期是当前月份,然后与上一条记录的enddate进行比较,如果差距大于3个月,则打印'是',否则打印'否'。

顺便提一下:下面的activerec字段表示如果ID具有当前月份的开始日期,则显示为是。

例如,表数据如下:

ID   startdate  enddate  name.  activerec 
101 03-01-2023. 11-30-2023 Lee     yes
101 02-01-2023  02-28-2023 Lee     No
101 12-01-2022  12-31-2022 Lee     No
102 03-01-2023  03-31-2023 Mark    yes
102 10-01-2022. 10-31-2022 Mark.   No

我需要的答案如下:

ID   startdate  enddate  name activerec     
101 03-01-2023. 11-30-2023 Lee     yes
101 02-01-2023  02-28-2023 Lee     No
101 12-01-2022  12-31-2022 Lee     No
102 03-01-2023  03-31-2023 Mark    yes
102 10-01-2022. 10-31-2022 Mark.   No

Flag
No
No
No
Yes
No
No

这里101号ID具有当前月份的开始日期,上一条记录的结束日期是02-28-2023。我需要比较当前月的开始日期03-01-2023和02-28-2023,看是否相差三个月以上。这个ID的时间差不到3个月,所以我需要打印'No'。

102号ID具有当前月份的开始日期,而上一条记录的结束日期是10-31-2022,相差超过3个月。因此,我需要将其视为新成员,并打印'Yes'。"

英文:

There are same IDs in multiple records with different startdate and enddate spans.

I need to write a teradata sql case condition to check by ID and whose start date is current month and compare with enddate of previous record

Case condition:
I need to write a teradata sql case condition to check by ID and whose start date is current month and compare with enddate of previous record, if there is a difference greater than 3 months then print 'yes' else 'no'

Just FYI: below activerec field is if the ID has a start date of current month it is shown as yes.

Example the table data is as below:

ID   startdate  enddate  name.  activerec 
101 03-01-2023. 11-30-2023 Lee     yes
101 02-01-2023  02-28-2023 Lee     No
101 12-01-2022  12-31-2022 Lee     No
102 03-01-2023  03-31-2023 Mark    yes
102 10-01-2022. 10-31-2022 Mark.   No

I need the answer as below:

ID   startdate  enddate  name activerec     
101 03-01-2023. 11-30-2023 Lee     yes
101 02-01-2023  02-28-2023 Lee     No
101 12-01-2022  12-31-2022 Lee     No
102 03-01-2023  03-31-2023 Mark    yes
102 10-01-2022. 10-31-2022 Mark.   No

Flag
No
No
No
Yes
No
No

Here 101 ID has a startdate as current month and the enddate of previous record date span is 02-28-2023. I need to compare current month's start date 03-01-2023 with 02-28-2023 to see if it has difference of three months or not. This ID doesn't have a difference of 3 months so I need to print 'No'.

102 ID has a startdate as current month and it's previous record end date 10-31-2022, it has a difference of more than 3 months. So, I need consider this a new member and print as 'Yes'.

I Couldn't do it at all

答案1

得分: 0

这是一个SQL翻译:

case   -- 开始日期是当前月
  when startdate = trunc(current_date, 'mm') 
       -- 差异大于3个月
   and add_months(lag(enddate) over (partition by id order by startdate), 3)
          < startdate 
  then 'y'
  else 'n' 
end
英文:

This is a translation to SQL:

case   -- start date is current month
  when startdate = trunc(current_date, &#39;mm&#39;) 
       -- difference greater than 3 months
   and add_months(lag(enddate) over (partition by id order by startdate), 3)
          &lt; startdate 
  then &#39;y&#39;
  else &#39;n&#39; 
end

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  • 本文由 发表于 2023年3月31日 04:40:34
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