英文:
Find remainder in bash
问题
以下是您提供的代码部分的中文翻译：
#!/bin/bash
read T
var0=0
while [[ "$var0" -lt "$T" ]]
do
read A B
echo $(( A % B ))
(( var0++ ))
done
如果您需要关于代码的任何进一步解释或帮助，请随时提问。
英文:
A codechef problem:
> Write a program to find the remainder when an integer A is divided by an integer B.
>
> ##### Input
>
> The first line contains an integer T, the total number of test cases. Then T lines follow, each line contains two Integers A and B.
>
> ##### Output
>
> For each test case, find the remainder when A is divided by B, and display it in a new line.
>
> ##### Constraints
>
> * 1 ≤ T ≤ 1000
> * 1 ≤ A,B ≤ 10000
This is my solution. It works with the sample numbers but when I submit it it fails a test. I'm pretty sure the code is correct. What might the problem be?
#!/bin/bash
read T
var0=0
while [[ "$var0" < "$T" ]]
do
read A B
echo $(( A % B ))
(( var0++ ))
done
答案1
得分: 2
你的代码在特定条件下运行良好，但没有在这里进行解释。我复制了它，保存为rem.bash，更改了权限以使其可执行，然后运行它。以下是会话结果：
$ rem.bash
3
1 3
1
2 3
2
4 3
1
第一个3是运行操作的次数。然后我输入：1 3。余数输出为1。在第三次迭代中，我输入：4 3。余数为1。循环退出，程序终止。
要使其适用于所有输入，请更改while行为
while ((var0 < t))
在bash算术中，((和))之间的内容，您不需要使用$来引用变量。您还可以使用标准的关系运算符。
英文:
Your code works fine under specific conditions not explained here. I copied it, saved it to rem.bash, changed the permission to make it executable, and ran it. The following is the session result:
$ rem.bash
3
1 3
1
2 3
2
4 3
1
The first 3 is the number of times to run the operation. I then entered: 1 3. The remainder is output as 1. On the third iteration, I entered: 4 3. The remainder is 1. The loop exited, and the program terminated.
To make it work for all inputs, change the while line to
while ((var0 < t))
In bash arithmetic, stuff between (( and )), you don't need $ to dereference the variable. You can also use standard relational operators.
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