Map the split to trim each entry

I need to write a function that takes a string as an input, splits it by the line break character and trims all the redundant break characters in each entry of the split. I've come up with the following:

fn split_and_trim(text: &String) {
    let lines - text.split('\n').map(|l| String::from(l).trim());
    println!("{:?}", lines)
}

But this code returns me the following error:

6 |     let lines = text.map(|l| String::from(l).trim());
  |                                   ---------------^^^^^^^
  |                                   |
  |                                   returns a reference to data owned by the current function
  |                                   temporary value created here

Trying to rewrite it the following way:

let lines: Vec<String> = text.split('\n').map(|l| String::from(l).trim()).collect();

Returns another error:

value of type `Vec<String>` cannot be built from `std::iter::Iterator<Item=&str>`

What would be the correct way of achieving this goal (splitting the string and trimming the each element)? Thanks in advance!

You don't need to create new Strings here, since trim only needs slices. (playground)

fn split_and_trim(text: &str) {
    let lines: Vec<&str> = text.split('\n').map(|l| l.trim()).collect();
    println!("{:?}", lines)
}

You should also take &str instead of &String as a function parameter in almost all cases.

If you need Strings, you can convert them after trimming.