Why does the "&" sign not print the variable address when passed to fmt.Print?

I have some code, that print a message "Hello and welcome to educative in 2021"

package main
import (
  "fmt"
  "bytes"
)
func main() {
  // declaring variables of different datatypes
  var message string = "Hello and welcome to "
  var year int = 2021
  // temporary buffer
  var temp_buff bytes.Buffer
  // printing out the declared variables as a single string
  fmt.Fprintf(&temp_buff, "%s educative in %d",  message, year)
  fmt.Print(&temp_buff)
}

I expected the last fmt.Print to print the address to the temp_buff variable. Why is this not happening? I don't see the temp_buffer variable being defined as a pointer type to bytes.Buffer or is it somehow?

Thanks in advance.

There is a func (*bytes.Buffer) String() method declared, so fmt.Print() uses it.

fmt.Print "formats using the default formats for its operands". The defaults follow the convention that if the type of the value defines a String() method, then that method is how it will be displayed. The details are related to the fmt.Stringer interface type.

With fmt.Printf() you can get what you want, by using a fmt.Printf("%p", &temp_buff).

In Go, printing a structure will automatically call the String() method, even if it receives a pointer type, it will be automatically converted to a value type and printed as a string. This is the difference from printing primitive types.