如何将 StartsWith() 作为参数传递给 Expression.Call()?

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英文:

How to pass StartsWith() as a parameter to Expression.Call()?

问题

I'm trying to call the StartsWith() function as an expression and pass a constant to it.

var textConstant = Expression.Constant(text);
var startsWith = Expression.Call(StartsWith, textConstant); // something like this

I'm new to C#, and I couldn't figure out how to pass these into Expression.Call().

英文:

Im trying to call StartsWith() function as an expression and pass a constant to it.

var textConstant =Expression.Constant(text);
var startsWith = Expression.Call(StartsWith ,textConstant); //something like this

Im new to c# and I couldn't figure out how to pass these into Expression.Call().

答案1

得分: -1

这是示例:

string text = "Some string";
string startsText = "Some";

Expression callExpr = Expression.Call(
                      Expression.Constant(text), 
                      typeof(String).GetMethod("StartsWith", 
                                     new Type[] { typeof(String) }),
                      Expression.Constant(startsText));
					
// 打印表达式
Console.WriteLine(callExpr);
					
// 执行表达式
var lambda = Expression.Lambda<Func<bool>>(callExpr).Compile();
Console.WriteLine(lambda());
英文:

Here is sample:

 string text = &quot;Some string&quot;;
 string startsText = &quot;Some&quot;;
		
 Expression callExpr = Expression.Call(
                          Expression.Constant(text), 
                          typeof(String).GetMethod(&quot;StartsWith&quot;, 
                                         new Type[] { typeof(String) }),
                          Expression.Constant(startsText));
		
 // print the expression
 Console.WriteLine(callExpr);
		
 // execute the expression
 var lambda = Expression.Lambda&lt;Func&lt;bool&gt;&gt;(callExpr).Compile();
 Console.WriteLine(lambda());

huangapple
  • 本文由 发表于 2023年3月21日 01:46:38
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