如何在Go中从for循环中返回接口列表?

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英文:

How to return interface list from a for loop in Go?

问题

如何从Go的for循环中返回接口列表?

假设我有以下数据:

id name project_type
1 project_name 1
2 project_name 1
3 project_name 1
4 project_name 2
5 project_name 2
6 project_name 3
7 project_name 3
8 project_name 3
9 project_name 4
10 project_name 4

我可以使用以下Go代码获取project_type=1和project_type=2的两个列表:

func (d *db) ProjectList(Type, uid string, size uint64) (interface{}, interface{}, error) {
    type resp struct {
        Name            string  `json:"name"`
        Id             string  `json:"id"`
        ProjectType    string  `json:"project_type"`

    }

    var project_type_1 []*resp
    var project_type_2 []*resp

    sql = fmt.Sprintf(sql, where.String())
    _, err := d.ctx.DB().SelectBySql("select * from project where project_type=1 order by rand() limit 10").Load(&project_type_1)

    _, err = d.ctx.DB().SelectBySql("select * from project where project_type=2 order by rand() limit 10").Load(&project_type_2)
    return project_type_1, project_type_2, err
}

但是现在project_type的数据是一个JSON,格式为[{"project_type":1,"name":"something else"},{"project_type":2,"name":"something else"},{"project_type":3,"name":"something else"},{"project_type":4,"name":"something else"}],project_type的值超过2个,我需要获取一个接口{}列表。我尝试将代码重写如下,但是我不知道接下来该如何编写,如何从Go的for循环中返回接口列表?非常感谢任何建议。

func NewProjectList(d *db) ([]interface{}, error) {
    var s = make([]ProjectType, 0)
    data, err := d.QueryString("project_type")
    if err != nil {
        return nil, err
    }

    err = json.Unmarshal([]byte(data), &s)
    if err != nil {
        return nil, err
    }

    for _, shortType := range s {
        fmt.Println("this is shortType", shortType)
    }
    return nil, err

}
英文:

How to return interface list from a for loop in Go?
Supposed I have data as below:

id name project_type
1 project_name 1
2 project_name 1
3 project_name 1
4 project_name 2
5 project_name 2
6 project_name 3
7 project_name 3
8 project_name 3
9 project_name 4
10 project_name 4

I can use the below go code to get two list of project_type=1 and project_type=2,

func (d *db) ProjectList(Type, uid string, size uint64) (interface{}, interface{}, error) {
    type resp struct {
        Name            string  `json:"name"`
        Id             string  `json:"id"`
        ProjectType    string  `json:"project_type"`

    }

    var project_type_1 []*resp
    var project_type_2 []*resp

    sql = fmt.Sprintf(sql, where.String())
    _, err := d.ctx.DB().SelectBySql("select * from project where project_type=1 order by rand() limit 10").Load(&project_type_1)

    _, err = d.ctx.DB().SelectBySql("select * from project where project_type=2 order by rand() limit 10").Load(&project_type_2)
    return project_type_1, project_type_2, err
}

But now the data of project_type is a JSON of [{"project_type":1,"name":"something else"},{"project_type":2,"name":"something else"},{"project_type":3,"name":"something else"},{"project_type":4,"name":"something else"}], project_type is more than 2, I have to get a interface{} list, I tried to re-write code as below, But I don't know how do write next, How to return interface list from a for loop in Go?, thanks so much for any advice.

func NewProjectList(d *db) ([]interface{}, error) {
    var s = make([]ProjectType, 0)
    data, err := d.QueryString("project_type")
    if err != nil {
        return nil, err
    }

    err = json.Unmarshal([]byte(data), &s)
    if err != nil {
        return nil, err
    }

    for _, shortType := range s {
        fmt.Println("this is shortType", shortType)
    }
    return nil, err

}

答案1

得分: 1

如果你想让每个project_type都有10个结果(总共10*n个结果):

func (d *db) ProjectList(Type, uid string, size uint64) ([]interface{}, error) {
	type resp struct {
		Name        string `json:"name"`
		Id          string `json:"id"`
		ProjectType string `json:"project_type"`
	}
	// 获取所有类型,你可以从数据库中获取
	// 例如:select DISTINCT ProjectType from project
	types := []string{"1", "2", "3", "4"}
	ans := []interface{}{}

	for _, sType := range types {
		var project_type []*resp
		sql := fmt.Sprintf("select * from project where project_type=%s order by rand() limit 10", sType)
		_, err := d.ctx.DB().SelectBySql(sql).Load(&project_type)
		ans = append(ans, project_type)
	}
	return ans, nil
}

如果所有类型总共只有10个结果:

// 如果需要,我可以为你编写这部分代码
英文:

if you want each project_type have 10 results(all 10*n results):

func (d *db) ProjectList(Type, uid string, size uint64) ([]interface{}, error) {
	type resp struct {
		Name        string `json:"name"`
		Id          string `json:"id"`
		ProjectType string `json:"project_type"`
	}
	// get all types, you can get it from db
	// example: select DISTINCT ProjectType from project
	types := []string{"1", "2", "3", "4"}
	ans := []interface{}{}

	for _, sType := range types {
		var project_type []*resp
		sql = fmt.Sprintf(sql, where.String())
		_, err := d.ctx.DB().SelectBySql("select * from project where project_type=" + sType + " order by rand() limit 10").Load(&project_type)
		ans = append(ans, project_type)
	}
	return ans, nil
}

if A total of 10 results for all types:

 i write it if you need it

huangapple
  • 本文由 发表于 2023年3月17日 15:10:25
  • 转载请务必保留本文链接:https://go.coder-hub.com/75764651.html
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