ggplot2根据数据拆分颜色直方图:facet_grid

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英文:

ggplot2 split color histograms according to data: facet_grid

问题

建立在这个问题的基础上:

是否有一种方法可以创建一个直方图网格,其中在任意值上方和下方的柱子有不同的颜色(无重叠的柱子),而不需要引用ggplot()之外的环境?我可以使用单个直方图做到这一点,就像这样(仅用中位数进行说明):

set.seed(123)

value = stats::rnorm(100, mean = 0, sd = 1)

df = data.frame(value)

df %>%
  {
    ggplot(data = ., aes(x = value, fill = ifelse(value > median(value), "0", "1"))) +
      geom_histogram(boundary = median(.$value), alpha = 0.5, position = "identity") +
      theme(legend.position = "none")
  }

ggplot2根据数据拆分颜色直方图:facet_grid

是否可以为分面图创建这样的效果,其中每个图根据一个分组变量使用不同的值?例如,这个方法不起作用:

set.seed(456)

value = stats::rnorm(200, mean = 0, sd = 1)
group = c(rep(1,100), rep(2,100))

df = data.frame(value, group)

df %>%
  dplyr::mutate(value = ifelse(group == 2, value + 1, value)) %>%
  dplyr::group_by(group) %>%
  dplyr::mutate(above_median = value > median(value)) %>%
  {
    ggplot(data = ., aes(x = value, fill = above_median)) +
      facet_grid(rows = group) +
      geom_histogram(boundary = median(.$value), alpha = 0.5, position = "identity") +
      theme(legend.position = "none")
  }

ggplot2根据数据拆分颜色直方图:facet_grid

英文:

Building on this question:

Is there a way to create a grid of histograms where the bins are different colors above vs. below arbitrary values (without overlapping bins), without needing to refer to the environment outside of ggplot()? I can do this with a single histogram, like this (using median for illustration purposes):

set.seed(123)

value = stats::rnorm(100, mean = 0, sd = 1)

df = data.frame(value)

df %>%
  {
    ggplot(data = ., aes(x = value, fill = ifelse(value > median(value), "0", "1"))) +
      geom_histogram(boundary = median(.$value), alpha = 0.5, position = "identity") +
      theme(legend.position = "none")
  }

ggplot2根据数据拆分颜色直方图:facet_grid

Can this be done for faceted plots, where each plot uses a different value, according to a grouping variable? E.g. this doesn't work:

set.seed(456)

value = stats::rnorm(200, mean = 0, sd = 1)
group = c(rep(1,100), rep(2,100))
    
df = data.frame(value, group)

df %>%
  dplyr::mutate(value = ifelse(group == 2, value + 1, value)) %>%
  dplyr::group_by(group) %>%
  dplyr::mutate(above_median = value > median(value)) %>%
  {
    ggplot(data = ., aes(x = value, fill = above_median)) +
      facet_grid(rows = group) +
      geom_histogram(boundary = median(.$value), alpha = 0.5, position = "identity") +
      theme(legend.position = "none")
  }

ggplot2根据数据拆分颜色直方图:facet_grid

答案1

得分: 2

以下是代码部分的中文翻译:

一种选项是使用多个 geom_histogram 层来添加直方图,即按组拆分数据,然后使用 lapply 为每个组添加一个 geom_histogram

library(dplyr, warn=FALSE)
library(ggplot2)

df %>%
  dplyr::mutate(value = ifelse(group == 2, value + 1, value)) %>%
  dplyr::group_by(group) %>%
  dplyr::mutate(above_median = value > median(value)) %>%
  {
    ggplot(data = ., aes(x = value, fill = above_median)) +
      facet_grid(rows = vars(group)) +
      lapply(split(., .$group), function(x) {
        geom_histogram(data = x, boundary = median(x$value), alpha = 0.5, position = "identity")
      }) +
      theme(legend.position = "none")
  }
#> `stat_bin()` 使用 `bins = 30`。使用 `binwidth` 选择更好的值。
#> `stat_bin()` 使用 `bins = 30`。使用 `binwidth` 选择更好的值。

ggplot2根据数据拆分颜色直方图:facet_grid

英文:

One option would be to add you histograms using multiple geom_histogram layers, i.e. split your data by group, then use lapply to add a geom_histogram for each group:

library(dplyr, warn=FALSE)
library(ggplot2)

df %>%
  dplyr::mutate(value = ifelse(group == 2, value + 1, value)) %>%
  dplyr::group_by(group) %>%
  dplyr::mutate(above_median = value > median(value)) %>%
  {
    ggplot(data = ., aes(x = value, fill = above_median)) +
      facet_grid(rows = vars(group)) +
      lapply(split(., .$group), function(x) {
        geom_histogram(data = x, boundary = median(x$value), alpha = 0.5, position = "identity")
      }) +
      theme(legend.position = "none")
  }
#> `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
#> `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.

ggplot2根据数据拆分颜色直方图:facet_grid<!-- -->

答案2

得分: 2

这是我解决问题的方式,但@stefan的答案更好(+1)。

library(tidyverse)

set.seed(456)

value = stats::rnorm(200, mean = 0, sd = 1)
group = c(rep(1,100), rep(2,100))

df = data.frame(value, group)

df %>% 
  dplyr::mutate(value = ifelse(group == 2, value + 1, value)) %>% 
  dplyr::group_by(group) %>% 
  dplyr::mutate(above_median = value > median(value)) %>% 
  ungroup() %>% 
  group_split(group) %>% 
  map(~{
    ggplot(data = .x, aes(x = value, fill = above_median)) +
      facet_grid(rows = .x$group) +
      geom_histogram(boundary = median(.x$value), alpha = 0.5, position = "identity") +
      theme(legend.position = "none")
  })
#> [[1]]
#> `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.

ggplot2根据数据拆分颜色直方图:facet_grid

#>
#> [2]
#> stat_bin() using bins = 30. Pick better value with binwidth.

ggplot2根据数据拆分颜色直方图:facet_grid

创建于2023年03月16日,使用 reprex v2.0.2

英文:

This is how I would tackle the problem, but @stefan's answer is better (+1),

library(tidyverse)

set.seed(456)

value = stats::rnorm(200, mean = 0, sd = 1)
group = c(rep(1,100), rep(2,100))

df = data.frame(value, group)

df %&gt;%
  dplyr::mutate(value = ifelse(group == 2, value + 1, value)) %&gt;%
  dplyr::group_by(group) %&gt;%
  dplyr::mutate(above_median = value &gt; median(value)) %&gt;%
  ungroup() %&gt;%
  group_split(group) %&gt;%
  map(~{
    ggplot(data = .x, aes(x = value, fill = above_median)) +
      facet_grid(rows = .x$group) +
      geom_histogram(boundary = median(.x$value), alpha = 0.5, position = &quot;identity&quot;) +
      theme(legend.position = &quot;none&quot;)
  })
#&gt; [[1]]
#&gt; `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.

ggplot2根据数据拆分颜色直方图:facet_grid<!-- -->

#&gt; 
#&gt; [[2]]
#&gt; `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.

ggplot2根据数据拆分颜色直方图:facet_grid<!-- -->

<sup>Created on 2023-03-16 with reprex v2.0.2</sup>

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  • 本文由 发表于 2023年3月15日 21:27:14
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