英文:
Django custom tags requires 3 arguments, 2 provided
问题
#custom_tags.pydef modulo(value, number, number2):mod = value % numberif mod == number2:return Trueelse:return False
{% comment %} index.html {% endcomment %}{% for post in posts|slice:"1:" %}{% if post.id|modulo:4:0 %}<div class="post-entry-1"><a href="{{post.slug}}"><img src="{{post.image.url}}" alt="" class="img-fluid"></a><div class="post-meta"><span class="date">{{post.category}}</span> <span class="mx-1">&bullet;</span> <span>{{post.created_date}}</span></div><h2><a href="single-post.html">{{ post.title }}</a></h2></div>{% endif %}{% endfor %}
TemplateSyntaxError at /blog/ modulo requires 3 arguments, 2 provided
当我使用变量 number 对值进行取模运算时，我想用变量 number2 检查结果。
英文:
#custom_tags.pydef modulo(value, number,number2):mod = value % numberif mod == number2:return Trueelse:return False
{% comment %} index.html {% endcomment %}{% for post in posts|slice:"1:"%}{% if post.id|modulo:4:0 %}<div class="post-entry-1"><a href="{{post.slug}}"><img src="{{post.image.url}}" alt="" class="img-fluid"></a><div class="post-meta"><span class="date">{{post.category}}</span> <span class="mx-1">&bullet;</span> <span>{{post.created_date}}</span></div><h2><a href="single-post.html">{{ post.title }}</a></h2></div>{% endif %}{% endfor %}
> TemplateSyntaxError at /blog/ modulo requires 3 arguments, 2 provided
When I mod the value with the variable number, I want to check the result with the variable number2
答案1
得分: 3
你定义了一个过滤器，而不是一个标签。标签最多可以带两个参数，一个是标签应用的对象，另一个是可选参数。
你可以这样定义一个标签：
from django import templateregister = template.Library()@register.simple_tagdef modulo(value, number, number2=0):return value % number == number2
然后你可以这样使用它：
{% modulo post.id 4 as md %}{% if md %}…{% endif %}
尽管如此，你的模板似乎实现了业务逻辑。这不应该放在模板中，而应该放在视图中。
英文:
You defined a filter, not a tag. A tag can (at most) take two parameters. The object on which the tag is applied and an optional parameter.
You can define a tag with:
<pre><code>from django import template
register = template.Library()
@register<b>.simple_tag</b>
def modulo(value, number, number2=0):
return value % number == number2</code></pre>
Then you use this with:
<pre><code>{% <b>modulo post.id 4 as md</b> %}
{% if md %}
…
{% endif %}</code></pre>
That being said, your template seems to implement business logic. This does not belong in the template, but in the view.
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