我想访问一些树节点的属性之一，它们的名称类似于“image1、image2，...”，所以我发现全局变量很酷，可以避免编写重复的代码；但是使用全局变量，我无法访问属性；我是 Python 新手，所以是的，我是新手。
这是我的代码：
```python
Image1=Node("I1", path="path", parent=Images, priceL=prices[0:12], fp=np.array([70,172]))
print(globals()["Image"+str(image)+".path"])

print(globals()["Image"+str(image)+".path"])
        ~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^
KeyError: 'Image1.path'

print(globals()[f"Image{str(image)}.path"])

<details>
<summary>英文:</summary>
I wanna access one of attributes of some of my tree nodes and their name is like &quot;image1,imag2,...&quot; so I found globals cool to avoid writing duplicated codes; but using globals i couldn&#39;t access attributes; i new to python so yup I&#39;m newbie.
this is my code:

there is errors:

i tried:
 print(globals()[f"Image{str(image)}.path"])
and storing the globals outcome in an other variable but its not how it works.
</details>
# 答案1
**得分**: 0
步骤1 ==&gt; 首先从全局变量中检索节点对象。
步骤2 ==&gt; 使用getattr()函数访问节点的属性。
Image1 = Node("I1", path="路径", parent=Images, priceL=prices[0:12], fp=np.array([70,172]))
node = globals()["Image" + str(image)]
path = getattr(node, "path")
print(path)
<details>
<summary>英文:</summary>
Step:1 ==&gt; First retrieve the node object from globals()
Step:2 ==&gt;  Use getattr() function to access the attribute of the node.
   
    Image1 = Node(&quot;I1&quot;, path=&quot;path&quot;, parent=Images, priceL=prices[0:12], fp=np.array([70,172]))
    node = globals()[&quot;Image&quot; + str(image)] 
    path = getattr(node, &quot;path&quot;) 
    print(path)
</details>