问题

我想封装Jackson的ObjectMapper类，将其转换为单例工具类。

但是单例类没有构造函数，我不知道应该怎么办？

我希望实现这样一个功能，请参见下面的伪代码：

object Jackson: ObjectMapper() = jacksonObjectMapper().configure(DeserializationFeature.FAIL_ON_IGNORED_PROPERTIES, false)

英文:

I want to wrap Jacksons ObjectMapper class and turn it into a single instance tool class.

But the singleton class has no constructor, I don't know what should I do?

I hope to achieve such a function, see the pseudo code below:

object Jackson: ObjectMapper() = jacksonObjectMapper().configure(DeserializationFeature.FAIL_ON_IGNORED_PROPERTIES, false)

答案1

得分: 2

我认为最简单的方法是将ObjectMapper实例包装在一个命名对象中：

object Jackson {
    val mapper = jacksonObjectMapper().configure(DeserializationFeature.FAIL_ON_IGNORED_PROPERTIES, false)
}

然后使用Jackson.mapper访问它。我不知道更简洁的方法来创建或使用Java类的单例。

英文:

I assume the most straightforward way would be to just wrap the ObjectMapper instance in a named object:

object Jackson {
    val mapper = jacksonObjectMapper().configure(DeserializationFeature.FAIL_ON_IGNORED_PROPERTIES, false)
}

And access it with Jackson.mapper. I am not aware of a more concise way to create or use a singleton for a java class.

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