英文:
\ and $ character in bash script
问题
我有一个脚本：
text=test
echo ""\Plugins$text" 正在计算 ""\Plugins$text""
如何编辑这个命令，以便它显示 `"\Plugins\test\`？
英文:
I have a script:
text=test
echo "\Plugins$text" is couting "\Plugins$text"
How to edit this command, so it displays "\Plugins\test\?
答案1
得分: 1
Because $text is a parameter expansion, you need to escape the $ to produce a literal $; that's what you are currently doing. You want a literal backslash instead; you need to escape the \ itself.
你需要转义 $，因为 $text 是参数展开，这样才能产生字面的 $；这是你目前正在做的事情。你想要一个字面的反斜杠，所以你需要转义 \ 本身。
You don't need to escape the initial backslash, because \P has no special meaning in a double-quoted string, and so a literal backslash is retained.
你不需要转义初始的反斜杠，因为在双引号字符串中，\P 没有特殊含义，所以会保留一个字面的反斜杠。
$ echo "\Plugins\\$text"
\Plugins\test
因为 `echo` 的行为在各种不同的 shell 中可以大不相同，如何创建结果中的 `\t` 会变化，所以更好的做法是为了一致性使用 `printf`。
$ printf '%s\n' "\Plugins\$text"
\Plugins\test
英文:
Because $text is a parameter expansion, you need to escape the $ to produce a literal $; that's what you are currently doing. You want a literal backslash instead; you need to escape the \ itself.
You don't need to escape the initial backslash, because \P has no special meaning in a double-quoted string, and so a literal backslash is retained.
$ echo "\Plugins\$text"
\Plugins\test
Because the behavior of echo can vary wildly from shell to shell in how it creates the resulting \t, it would be better to use printf for consistency.
$ printf '%s\n' "\Plugins\$text"
\Plugins\test
答案2
得分: 1
当字符串中可能包含 \ 时，我建议使用 printf 而不是 echo：
text=test
printf ''"\\Plugins\\%s\\ is couting \\Plugins\\%s\\"\n' "$text" "$text"
""\Plugins\test\ is couting \Plugins\test\""
英文:
When the string can contain \, I would recommend printf over echo:
text=test
printf '"\\Plugins\\%s\\ is couting \\Plugins\\%s\\"\n' "$text" "$text"
"\Plugins\test\ is couting \Plugins\test\"
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