如何在PHP中将JSON值更改为名称和值？

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英文:

How to change JSON Value to Name and Value? in PHP

问题

I have List of IDs in JSON

Here it is: https://temp.9animetv.live/api.php

it look like this

  1.  { "result": [
  2.     548915,
  3.     505031,
  4.     28967,
  5.     520928,
  6.     441762,
  7.     381418,
  8.     61650,
  9.     249457,
  10.     535995,
  11.     550023,
  12.       and more.. and more.. and more..  ]
  13. }

I want to change it to be like this

  1. { 
  2.     "result": [
  3.         {"id": 548915,}, 
  4.         {"id": 505031,}, 
  5.         {"id": 28967,},
  6.         {"id": 28967,}, 
  7.         {"id": 28967,}
  8.       ] 
  9. }

How to do that? Am using PHP

I have Tried

To change it to Array using Json_decode But still haven't figured out a way to do as I expected.

英文:

I have List of IDs in JSON

Here it is: https://temp.9animetv.live/api.php

it look like this

  1.  { "result": [
  2.     548915,
  3.     505031,
  4.     28967,
  5.     520928,
  6.     441762,
  7.     381418,
  8.     61650,
  9.     249457,
  10.     535995,
  11.     550023,
  12.       and more.. and more.. and more..
  13.    ]
  14. }

I want to change it to be like this

  1. { 
  2.     "result": [
  3.         {"id": 548915,}, 
  4.         {"id": 505031,}, 
  5.         {"id": 28967,},
  6.         {"id": 28967,}, 
  7.         {"id": 28967,}
  8.       ] 
  9. }

How to do that? Am using PHP

I have Tried

To change it to Array using Json_decode But still haven't figured out a way to do as I expected

答案1

得分: 1

只需读取JSON字符串，使用json_decode()将其转换为PHP等效对象，处理ID数组并创建一个新数组，然后将其再次转换为JSON字符串。

  1. $j_str = file_get_contents('https://temp.9animetv.live/api.php');
  2. $j_arr = json_decode($j_str);
  3. $new = [];
  4. foreach ($j_arr->result as $occ) {
  5.     $new[] = ['id' => $occ];
  6. }
  7. echo json_encode($new);

结果：

  1. [
  2.     {
  3.         "id": 548915
  4.     },
  5.     {
  6.         "id": 505031
  7.     },
  8.     {
  9.         "id": 28967
  10.     },
  11.     // ...
  12. ]

你可以跳过JSON_PRETTY_PRINT，那只是为了方便阅读输出以进行检查。

英文:

Simply read the json string, convert it to a PHP equivalent object using json_decode()
process the array of id's and create a new array which you then convert back to a JSON String

  1. $j_str = file_get_contents('https://temp.9animetv.live/api.php');
  2. $j_arr = json_decode($j_str);
  3. $new = [];
  4. foreach ( $j_arr->result as $occ ) {
  5.     $new[] = ['id' => $occ];
  6. }
  7. echo json_encode($new, JSON_PRETTY_PRINT);

RESULTS

  1. [
  2.     {
  3.         "id": 548915
  4.     },
  5.     {
  6.         "id": 505031
  7.     },
  8.     {
  9.         "id": 28967
  10.     },
  12.     . . .

You can skip the , JSON_PRETTY_PRINT, thats only I could easily read the output for checking

huangapple
  • 本文由 发表于 2023年3月9日 21:31:33
  • 转载请务必保留本文链接：https://go.coder-hub.com/75685292.html
  • arrays
  • json
  • php
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