Create function in interface with name from const in Typescript

Is it possible to create function in interface with name from const? I have const where I have all event names and I want to create ServerToClientEvents interface for SocketIO.

I can write something like this and it will work

interface A {
    "funcName": () => void
}

But can I create functions in this interface with names from FunNames?

export const Events = {
    user_updated: "user:updated",
    empty: "empty"
}

interface ServerToClientEvents {
    Events.empty: () => void;
    Events.user_updated: (user: User) => void;
}   

If Events isn't dynamic, maybe const assertion can do the job.

export const Events = {
    user_updated: 'user:updated',
    empty: 'empty',
} as const;   //const assertion

interface User {
    id: string;
}
interface ServerToClientEvents {
    [Events.empty]: () => void;
    [Events.user_updated]: (user: User) => void;
}

You can do it with a mapped type and a nested conditional type testing the key we're mapping to see if it matches a template literal type (so we detect whether we need the user parameter):

export const Events = {
    user_updated: "user:updated",
    empty: "empty",
};

type ServerToClientEvents = {
    [Key in keyof typeof Events]: Key extends `user_${string}` ? (user: User) => void : () => void;
};

const goodExample: ServerToClientEvents = {
    user_updated(user: User) {},
    empty() {},
};

const badExample: ServerToClientEvents = {
    //^^^^^^^^^^^−−−−− Property 'empty' is missing in type '{ user_updated(user: User): void; }' but required in type 'ServerToClientEvents'.ts(2741)
    user_updated(user: User) {},
};

Playground link

I've assumed there that the user_ prefix should mean the function accepts a User object, given the code shown in the question, but of course you can tweak that as necessary.

With the given Events constant, that mapped typ defines this structure:

{
    user_updated: (user: User) => void;
    empty: () => void;
}

For readability, you might split out the conditional type:

type ServerFunctionType<Key extends string> =
    Key extends `user_${string}`
        ? (user: User) => void
        : () => void;

type ServerToClientEvents = {
    [Key in keyof typeof Events]: ServerFunctionType<Key>;
};

Playground link