英文:
Best way to Sort lists in Flutter
问题
我有两个列表，一个包含特定顺序中枚举的所有可能值（列表 A），第二个列表填充了其中一些枚举值/或空值/或全部（列表 B），但顺序是随机的。
我试图将列表 B 按照列表 A 的顺序排序。当数值缺失时，它们应该被跳过，但顺序应保持不变。
起初，我以为这很容易，但我无法在不弄乱代码的情况下处理它，我认为这可以更轻松地完成。
英文:
I have two lists, one containing all possible values of an enum in a special order (list A) and a second one which is filled with some of these enum values/or null/or all (list B) but the order is random.
What I am trying is to sort list B in the order of list A. When values are missing, they are skipped, but the order should stay the same.
In the first instance, I thought this is easy but I can‘t manage it without a mess of code and I think this could be done way easier.
答案1
得分: 1
为了在secondList中添加存在于firstList中的项目，此函数将执行以下操作：
List getMatchingItems() {
List newSortedList = [];
List<String> firstList = [
"ENUM1",
"ENUM2",
"ENUM3",
"ENUM4",
];
List<String> secondList = [
"ENUM2",
"ENUM4",
"ENUM5",
];
for (var ennum in secondList) {
if (firstList.contains(ennum)) {
newSortedList.add(ennum);
}
}
return newSortedList;
}
英文:
In order to add items in secondList that exists in firstList
this function will do so..
List getMatchingItems() {
List newSortedList = [];
List<String> firstList = [
"ENUM1",
"ENUM2",
"ENUM3",
"ENUM4",
];
List<String> secondList = [
"ENUM2",
"ENUM4",
"ENUM5",
];
for (var ennum in secondList) {
if (firstList.contains(ennum)) {
newSortedList.add(ennum);
}
}
return newSortedList;
}
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