删除Julia中的矩阵某些行。

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英文:

Delete certain rows of a matrix in julia

问题

我正在大学课程中学习Julia,我必须完成一个作业,但我不知道如何预处理数据。我有一个矩阵,其中模式分布在行中。其维度为1521x4。

第一个属性的取值范围是0到4,我想删除第一个属性值小于4的模式(行)。如何在Julia中做到这一点?

我知道Julia中有许多用于处理矩阵和数组的操作,但我找不到适合我的问题的操作。

我有以下代码:

using DelimitedFiles

files_and_dirs = readdir()
for f in files_and_dirs
    if filesize(f) == 0
        rm(f)
    end
end

filter(endswith(".lxyr"), files_and_dirs)

# 初始化一个包含1行和4列属性的矩阵
global dataset = zeros(1, 4)

# 134 = 我们想要读取的最大数
for count in 1:134
    name = "img" * string(count) * ".lxyr"
    if isfile(name) # 检查文件是否存在
        matrix = readdlm(name)
        global dataset = vcat(dataset, matrix) 
    end
end
英文:

I am learning julia in a university course and I have to do an assigment but I don't know how to preprocess the data. Hi have a matrix with patterns distributed in rows. Its dimension is 1521x4.

The first attribute take values from 0 to 4 and I want to delete patterns (rows) whose first attribute has a value of less than 4. How could I do it using Julia?

I know that there are a lot of operations to work with matrices and arrays in julia but I don't find a suitable one for my problem.

I have this code:

using DelimitedFiles

files_and_dirs = readdir()
for f in files_and_dirs
    if filesize(f) == 0
        rm(f)
    end
end

filter(endswith(".lxyr"), files_and_dirs)

#Inicializamos la matriz con 1 fila y el numero de atributos de columnas
global dataset = zeros(1,4)

#134 = Numero maximo que queremos leer
for count in 1:134
    name = "img"*string(count)*".lxyr"
    if isfile(name) #Checkeamos si existe
        matrix = readdlm(name)
        global dataset = vcat(dataset, matrix) 
    end
end

答案1

得分: 2

以下是您要翻译的代码部分:

我认为您的代码执行以下操作将您问题中的所有代码写成一行):
```python
dataset = [readdlm(name) for name in string.("img",1:134,".lxyr") if isfile(name) && filesize(name) > 0]

如果您要过滤具有至少4个值的第一行的矩阵数据集:

filter!(m -> all(m[1,:] .>= 4), matrices)

如果您有一个如下的矩阵:

m = collect(reshape(1:16,4,4))

然后,您可以使用以下代码选择具有超过某个阈值的值的行:

@view m[[all(row .>= 2) for row in eachrow(m)],:]

<details>
<summary>英文:</summary>

I think your code does this (all code from your question written in one line):

dataset = [readdlm(name) for name in string.("img",1:134,".lxyr") if isfile(name) && filesize(name) > 0]


It is not clear what you need - filter matrices of rows from a matrix

If you want to filter dataset for matrices that have in first row values of at least 4:

filter!(m -> all(m[1,:] .>= 4), matrices)


If you have a matrix such as:

m = collect(reshape(1:16,4,4))

Than you can select rows having values above some threshold with a code such as:

@view m[[all(row .>= 2) for row in eachrow(m)],:]


</details>



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  • 本文由 发表于 2023年3月9日 17:18:31
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