英文:
The variables are not recognized
问题
Set(VarAttachmentControl,JSON(Image1.Image,IncludeBinaryData));
Set(VarBase64,Mid(VarAttachmentControl, Find("","", VarAttachmentControl)+1, Len(VarAttachmentControl)-Find("","", VarAttachmentControl)-1));
在Power Apps中遇到了一个问题。变量未被识别。然而，当我在第一行使用";"而不是","时，一切正常。
但然后我无法使用第二个"Set"。它不会被识别。有办法解决这个问题吗？
Set(VarAttachmentControl;JSON(Image1.Image;IncludeBinaryData))
但然后我无法使用第二个"Set"。它不会被识别。有办法解决这个问题吗？
英文:
Set(VarAttachmentControl,JSON(Image1.Image,IncludeBinaryData));
Set(VarBase64,Mid(VarAttachmentControl, Find(",", VarAttachmentControl)+1, Len(VarAttachmentControl)-Find(",", VarAttachmentControl)-1));
I run into a problem in power apps. The variables are not recognized. However, when I use a ";" instead of "," in the first line, that goes well.
But then I can't use the second 'Set". It will not be recognized. Is there a weay to fix this?
Set(VarAttachmentControl;JSON(Image1.Image;IncludeBinaryData))
But then I can't use the second 'Set". It will not be recognized. Is there a weay to fix this?
答案1
得分: 1
从https://learn.microsoft.com/power-apps/maker/canvas-apps/global-apps#formula-separators-and-chaining-operator，如果您的区域设置中小数点分隔符是“，”，那么“列表分隔符”（用于分隔函数参数的令牌）变为“;”，而“链接运算符”（用于在同一表达式中分隔两个函数调用的内容）变为“;;”。由于您说在您的情况下使用“;”作为列表分隔符有效，因此您的表达式应写成如下形式：
Set(
VarAttachmentControl;
JSON(Image1.Image; JSONFormat.IncludeBinaryData));;
Set(
VarBase64;
Mid(
VarAttachmentControl;
Find(";", VarAttachmentControl) + 1;
Len(VarAttachmentControl) - Find(";", VarAttachmentControl) - 1
)
);;
英文:
From https://learn.microsoft.com/power-apps/maker/canvas-apps/global-apps#formula-separators-and-chaining-operator, if the decimal separator in your locale is ,, then the "list separator" (the token used to separate parameters to a function) becomes ;, and the "chaining operator" (what is used to separate two function calls in the same expression becomes ;;. Since you say that using ; as a list separator works in your scenario, your expression should be written as follows:
Set(
VarAttachmentControl;
JSON(Image1.Image; JSONFormat.IncludeBinaryData));;
Set(
VarBase64;
Mid(
VarAttachmentControl;
Find(","; VarAttachmentControl) + 1;
Len(VarAttachmentControl) - Find(","; VarAttachmentControl) - 1
)
);;
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