英文:
anagrams can be handled with regexp
问题
这是我的要求
const input = 'abcadbca';
const required = 'bca';
输入包含3个可能的字谜：`abc`，`bca`，`bca`；
所有这些都可以使用 `regexp` 进行选择吗？
我尝试过，但没有结果：
const str = 'abcadbca';
const reg = str.match(/(a|b|c)/g);
console.log(reg);
期望结果：`[a,b,c,][b,c,a],[b,c,a]`；
结果应为 `[a,b,c],[b,c,a]` - 前两个匹配重叠，所以取第一个匹配项。
英文:
here is my requirement
const input = 'abcadbca';
const required = 'bca';
the input contains 3 possibility anagrams as:abc,bca,bca;
is this all can be selected using regexp?
i tried it, but got not result:
const str = 'abcadbca';
const reg = str.match(/(a|b|c)/g);
console.log(reg);
result expectation: [a,b,c,][b,c,a],[b,c,a];
result should be [a,b,c],[b,c,a] - first 2 match are overlapping so first match is taken for the account.
答案1
得分: 1
const str = 'abcadbca';
console.log(str.match(/(?=.{0,2}b)(?=.{0,2}c)(?=.{0,2}a).{3}/g));
英文:
Since you know in advance the characters that constitute the anagrams you're expecting, as indicated by your required constant already consisting of characters b, c and a, you can build a regex with each character included in a sub-pattern that expects it in one of the following 3 characters with a lookahead pattern:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const str = 'abcadbca';
console.log(str.match(/(?=.{0,2}b)(?=.{0,2}c)(?=.{0,2}a).{3}/g));
<!-- end snippet -->
This outputs:
[
"abc",
"bca"
]
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