英文:
Filter null case when reading in keys from YAML with yq
问题
我可以翻译代码部分和相关的问题，不包括要翻译的内容。以下是代码和问题的翻译：
Say I have a yaml file, `example.yaml`:
test:
services:
registry:
image: registry:2
ports:
- "5000:5000"
- "337:337"
pinger:
build:
我可以将services读入一个bash数组，如下所示：
readarray -t services <<< $(yq e '.services | keys | .[]' example.yaml)
但是，当我尝试键没有子键的情况时，我会收到错误消息：
yq e '.test | keys | .[]' example.yaml
Error: Cannot get keys of !!null, keys only works for maps and arrays
有没有一种很好的方法来替换空值的情况并存储为假值？最终，我希望`test`存储为bash变量（== false）。
英文:
Say I have a yaml file, example.yaml:
test:
services:
registry:
image: registry:2
ports:
- "5000:5000"
- "337:337"
pinger:
build:
I can read in the services to a bash array like so:
readarray -t services <<< $(yq e '.services | keys | .[]' example.yaml)
But when I try the case where the key has no sub-keys, I get an error:
yq e '.test | keys | .[]' example.yaml
Error: Cannot get keys of !!null, keys only works for maps and arrays
What is a good way of replacing the null case with a falsey value? Ultimately I'd like test to be stored as a bash variable ( == false).
答案1
得分: 1
使用select()函数与not运算符结合在应用keys函数之前过滤掉空值，就像这样：
yq e '.test | select(.) | keys | .[]' example.yaml
select(.)表达式将返回test键中的所有非空值。您也可以对其他键使用相同的方法：
yq e '.test | select(.) | keys | .[]' example.yaml
yq e '.services | select(.) | keys | .[]' example.yaml
英文:
Use the select() function in combination with the not operator to filter out the null values before applying the keys function like this;
yq e '.test | select(.) | keys | .[]' example.yaml
The select(.) expression will return all non-null values in the test key. You can use the same approach for those keys as well:
yq e '.test | select(.) | keys | .[]' example.yaml
yq e '.services | select(.) | keys | .[]' example.yaml
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