英文:
TypeError: render_template() flask
问题
这是我的代码，错误出现如下。我不知道为什么。帮帮我。
from flask import url_for, session, Flask, request, redirect, render_templateapplication = Flask(__name__)application.secret_key = "sadqwwqds"@application.route("/")def home():if "userID" in session:return render_template("userid=session.get('username')", login=True)else:return render_template(login=False)@application.route("/login", methods=["get"])def login():pass@application.route("/logout")def logout():passapplication.run(host="0.0.0.0")
TypeError: render_template()缺少一个必需的位置参数: 'template_name_or_list'
127.0.0.1 - - [08/Mar/2023 15:28:11] "GET / HTTP/1.1" 500 -
我尝试修改HTML代码，但没有效果。
问题在哪里？
英文:
This is my code and the error appears ad below. i don't know why. help me
from flask import url_for, session, Flask, request, redirect, render_templateapplication = Flask(__name__)application.secret_key = "sadqwwqds"@application.route("/")def home():if "userID" in session:return render_template(userid=session.get("username"), login=True)else:return render_template(login=False)@application.route("/login", methods=["get"])def login():pass@application.route("/logout")def logout():pass
application.run(host="0.0.0.0")
TypeError: render_template() missing 1 required positional argument: 'template_name_or_list'
127.0.0.1 - - [08/Mar/2023 15:28:11] "GET / HTTP/1.1" 500 -
{% if login == True%}<meta charset="utf-8"><h3>login success {{username}}welcome</h3><a href = {{ url_for("logout") }}>logout</a>{%else %}<form methods = "get" id="login" action={{url_for("login")}}><input type ="id" id ="loginid" name="loginId" placeholder="input"><input type="password" id="loginPw" name="loginPw" placeholder="input"><button type="submit" class="login">login</button></form>{%endif%}`
I tried to modify the HTML code, but it din't work
where's the problem?
答案1
得分: 1
Flask的文档指出你需要指定template_name_or_list（参见https://flask.palletsprojects.com/en/2.2.x/api/#flask.render_template）
这里只指定了关键字参数，其中没有template_name_or_list：
@application.route("/")def home():if "userID" in session:return render_template(userid=session.get("username"), login=True)else:return render_template(login=False)
修改HTML不会有帮助，将模板名称传递给render_template在你的main.py中。我不知道你的路径，也不知道模板的名称，但带有占位符看起来像这样：
return render_template("<PATH_TO_YOUR_TEMPLATE>/<FILENAME>", userid=session.get("username"), login=True)
英文:
The documentation of Flask states that you have to specify template_name_or_list (see
https://flask.palletsprojects.com/en/2.2.x/api/#flask.render_template)
Here you specify only keyword arguments, none of which is the template_name_or_list:
@application.route("/")def home():if "userID" in session:return render_template(userid=session.get("username"), login=True)else:return render_template(login=False)
Modifying the HTML won't help, pass the template name to render_template in your main.py. I don't know your path, neither the name of the template, but with placeholder it looks like this:
return render_template("<PATH_TO_YOUR_TEMPLATE>/<FILENAME>", userid=session.get("username"), login=True)
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