将输入的小时转换为1/4小时的公式。

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英文:

Formula to use to convert the hours entered to 1/4th hour

问题

我正在创建一个Oracle快速公式,在其中我试图将员工输入的时间四舍五入到最近的1/4小时。

 15-22分钟 = 0.25小时
 23-37分钟 = 0.50小时
 38-52分钟 = 0.75小时
 53分钟到1小时7分钟 = 1小时

我能够获得输入的小时数。

例如 - 输入时间 - 下午5点 - 下午8.25点将是3.42小时。
现在这应该转换为最近的1/4小时 - 3.75。

要将这个转换为3.42小时,我应该使用什么计算公式?

英文:

I am creating a Oracle fast formula where I am trying to round the time entered by employee to the nearest 1/4 hour.

15-22  minutes = 0.25 hours
23- 37 minutes = 0.50 hours
38-52 minutes = 0.75 hours
53 to 1 hr 7 mins  = 1 hour

I am able to get the hours entered.

For Eg - Time entered - 5 PM - 8.25 PM will be 3.42 hours entered
Now this should be converted to the nearest 1/4 hour - 3.75.

what calculation formula should I use to convert this to 3.42 hours ?

答案1

得分: 2

通过使用Oracle的DATE差异进行一些算术运算。计算1表示一天,1 / (24 * 4)表示一个刻钟,您可以计算

with dt as (
select date'2023-01-01' + rownum/(24*60) date_dt from dual 
connect by level <= 24*60 - 1)
select date_dt,
round((date_dt - trunc(date_dt)) * 24 * 4) closest_qh,
trunc(date_dt) + round((date_dt - trunc(date_dt)) * 24 * 4) / (24 * 4) rounded_date,
round((date_dt - trunc(date_dt)) * 24 * 4) / 4 formula
from dt;

输出(为简洁起见删减)

DATE_DT             CLOSEST_QH ROUNDED_DATE           FORMULA
------------------- ---------- ------------------- ----------
...
01.01.2023 03:21:00         13 01.01.2023 03:15:00       3,25
01.01.2023 03:22:00         13 01.01.2023 03:15:00       3,25
01.01.2023 03:23:00         14 01.01.2023 03:30:00        3,5
01.01.2023 03:24:00         14 01.01.2023 03:30:00        3,5
...
01.01.2023 03:36:00         14 01.01.2023 03:30:00        3,5
01.01.2023 03:37:00         14 01.01.2023 03:30:00        3,5
01.01.2023 03:38:00         15 01.01.2023 03:45:00       3,75
01.01.2023 03:39:00         15 01.01.2023 03:45:00       3,75
...
01.01.2023 03:51:00         15 01.01.2023 03:45:00       3,75
01.01.2023 03:52:00         15 01.01.2023 03:45:00       3,75
01.01.2023 03:53:00         16 01.01.2023 04:00:00          4
01.01.2023 03:54:00         16 01.01.2023 04:00:00          4
英文:

With a bit of arithmetic using the Oracle DATE differenz. Calulation 1 is one day, 1 / (24 * 4) is a quartel of an hour, you may calculate

with dt as (
select date&#39;2023-01-01&#39; +  rownum/(24*60) date_dt from dual 
connect by level &lt;= 24*60 - 1)
select date_dt,
round((date_dt - trunc(date_dt)) * 24 * 4) closest_qh,
trunc(date_dt) + round((date_dt - trunc(date_dt)) * 24 * 4) / (24 * 4) rounded_date,
round((date_dt - trunc(date_dt)) * 24 * 4) / 4 formula
from dt;

output (cut for brevity)

DATE_DT             CLOSEST_QH ROUNDED_DATE           FORMULA
------------------- ---------- ------------------- ----------
...
01.01.2023 03:21:00         13 01.01.2023 03:15:00       3,25
01.01.2023 03:22:00         13 01.01.2023 03:15:00       3,25
01.01.2023 03:23:00         14 01.01.2023 03:30:00        3,5
01.01.2023 03:24:00         14 01.01.2023 03:30:00        3,5
...
01.01.2023 03:36:00         14 01.01.2023 03:30:00        3,5
01.01.2023 03:37:00         14 01.01.2023 03:30:00        3,5
01.01.2023 03:38:00         15 01.01.2023 03:45:00       3,75
01.01.2023 03:39:00         15 01.01.2023 03:45:00       3,75
...
01.01.2023 03:51:00         15 01.01.2023 03:45:00       3,75
01.01.2023 03:52:00         15 01.01.2023 03:45:00       3,75
01.01.2023 03:53:00         16 01.01.2023 04:00:00          4
01.01.2023 03:54:00         16 01.01.2023 04:00:00          4

答案2

得分: 1

你可以使用TRUNC将时间截断到小时的起始,然后将分钟和秒钟部分四舍五入到最近的15分钟,并添加:

SELECT time,
       TRUNC(time, 'HH') + ROUND((time - TRUNC(time, 'HH'))*4*24)/4/24 AS rounded_time
FROM   times

对于示例数据:

CREATE TABLE times (time) AS
SELECT TRUNC(SYSDATE, 'HH') + NUMTODSINTERVAL(LEVEL, 'MINUTE')
FROM   DUAL
CONNECT BY LEVEL <= 60;

输出:

TIME ROUNDED_TIME
2023-03-08 08:01:00 2023-03-08 08:00:00
... ...
2023-03-08 08:07:00 2023-03-08 08:00:00
2023-03-08 08:08:00 2023-03-08 08:15:00
... ...
2023-03-08 08:22:00 2023-03-08 08:15:00
2023-03-08 08:23:00 2023-03-08 08:30:00
... ...
2023-03-08 08:37:00 2023-03-08 08:30:00
2023-03-08 08:38:00 2023-03-08 08:45:00
... ...
2023-03-08 08:52:00 2023-03-08 08:45:00
2023-03-08 08:53:00 2023-03-08 09:00:00
... ...
2023-03-08 09:00:00 2023-03-08 09:00:00

fiddle

英文:

You can TRUNCate the time to the start of the hour and then round the minutes and seconds part to the nearest 15 minutes and add:

SELECT time,
       TRUNC(time, &#39;HH&#39;) + ROUND((time - TRUNC(time, &#39;HH&#39;))*4*24)/4/24 AS rounded_time
FROM   times

Which, for the sample data:

CREATE TABLE times (time) AS
SELECT TRUNC(SYSDATE, &#39;HH&#39;) + NUMTODSINTERVAL(LEVEL, &#39;MINUTE&#39;)
FROM   DUAL
CONNECT BY LEVEL &lt;= 60;

Outputs:

TIME ROUNDED_TIME
2023-03-08 08:01:00 2023-03-08 08:00:00
... ...
2023-03-08 08:07:00 2023-03-08 08:00:00
2023-03-08 08:08:00 2023-03-08 08:15:00
... ...
2023-03-08 08:22:00 2023-03-08 08:15:00
2023-03-08 08:23:00 2023-03-08 08:30:00
... ...
2023-03-08 08:37:00 2023-03-08 08:30:00
2023-03-08 08:38:00 2023-03-08 08:45:00
... ...
2023-03-08 08:52:00 2023-03-08 08:45:00
2023-03-08 08:53:00 2023-03-08 09:00:00
... ...
2023-03-08 09:00:00 2023-03-08 09:00:00

fiddle

答案3

得分: 0

这是我的理解(带有一些示例数据和逐步计算;只使用 result)。

SQL> with test (id, date_from, date_to) as
  2    (select 1, to_date('08.03.2023 17:00', 'dd.mm.yyyy hh24:mi'), to_date('08.03.2023 20:25', 'dd.mm.yyyy hh24:mi') from dual union all
  3     select 2, to_date('08.03.2023 17:00', 'dd.mm.yyyy hh24:mi'), to_date('08.03.2023 20:42', 'dd.mm.yyyy hh24:mi') from dual union all
  4     select 3, to_date('08.03.2023 17:00', 'dd.mm.yyyy hh24:mi'), to_date('08.03.2023 20:06', 'dd.mm.yyyy hh24:mi') from dual union all
  5     select 4, to_date('08.03.2023 17:00', 'dd.mm.yyyy hh24:mi'), to_date('08.03.2023 20:57', 'dd.mm.yyyy hh24:mi') from dual
  6    ),
  7  temp as
  8    (select id, date_from, date_to,
  9            numtodsinterval(date_to - date_from, 'day') diff
 10     from test
 11    )
 12  select id,
 13         to_char(date_from, 'hh24:mi') date_from,
 14         to_char(date_to  , 'hh24:mi') date_to,
 15         --
 16         diff,
 17         extract(hour from diff) hh,
 18         extract(minute from diff) mi,
 19         --
 20         case when extract(minute from diff) between 15 and 22 then 0.25
 21              when extract(minute from diff) between 23 and 37 then 0.50
 22              when extract(minute from diff) between 38 and 52 then 0.75
 23              when extract(minute from diff) < 14              then 0.00
 24              when extract(minute from diff) > 52              then 1.00
 25         end rnd,
 26         --
 27         extract(hour from diff) +
 28         case when extract(minute from diff) between 15 and 22 then 0.25
 29              when extract(minute from diff) between 23 and 37 then 0.50
 30              when extract(minute from diff) between 38 and 52 then 0.75
 31              when extract(minute from diff) < 14              then 0.00
 32              when extract(minute from diff) > 52              then 1.00
 33         end result
 34  from temp
 35  order by id;
英文:

This is how I understood it (with some sample data and step-by-step calculation; you'd use result only).

SQL&gt; with test (id, date_from, date_to) as
2    (select 1, to_date(&#39;08.03.2023 17:00&#39;, &#39;dd.mm.yyyy hh24:mi&#39;), to_date(&#39;08.03.2023 20:25&#39;, &#39;dd.mm.yyyy hh24:mi&#39;) from dual union all
3     select 2, to_date(&#39;08.03.2023 17:00&#39;, &#39;dd.mm.yyyy hh24:mi&#39;), to_date(&#39;08.03.2023 20:42&#39;, &#39;dd.mm.yyyy hh24:mi&#39;) from dual union all
4     select 3, to_date(&#39;08.03.2023 17:00&#39;, &#39;dd.mm.yyyy hh24:mi&#39;), to_date(&#39;08.03.2023 20:06&#39;, &#39;dd.mm.yyyy hh24:mi&#39;) from dual union all
5     select 4, to_date(&#39;08.03.2023 17:00&#39;, &#39;dd.mm.yyyy hh24:mi&#39;), to_date(&#39;08.03.2023 20:57&#39;, &#39;dd.mm.yyyy hh24:mi&#39;) from dual
6    ),

Query:

  7  temp as
8    (select id, date_from, date_to,
9            numtodsinterval(date_to - date_from, &#39;day&#39;) diff
10     from test
11    )
12  select id,
13         to_char(date_from, &#39;hh24:mi&#39;) date_from,
14         to_char(date_to  , &#39;hh24:mi&#39;) date_to,
15         --
16         diff,
17         extract(hour from diff) hh,
18         extract(minute from diff) mi,
19         --
20         case when extract(minute from diff) between 15 and 22 then 0.25
21              when extract(minute from diff) between 23 and 37 then 0.50
22              when extract(minute from diff) between 38 and 52 then 0.75
23              when extract(minute from diff) &lt; 14              then 0.00
24              when extract(minute from diff) &gt; 52              then 1.00
25         end rnd,
26         --
27         extract(hour from diff) +
28         case when extract(minute from diff) between 15 and 22 then 0.25
29              when extract(minute from diff) between 23 and 37 then 0.50
30              when extract(minute from diff) between 38 and 52 then 0.75
31              when extract(minute from diff) &lt; 14              then 0.00
32              when extract(minute from diff) &gt; 52              then 1.00
33         end result
34  from temp
35  order by id;
ID DATE_FROM  DATE_TO    DIFF                            HH  MI   RND     RESULT
--- ---------- ---------- ------------------------------ --- --- ----- ----------
1 17:00      20:25      +000000000 03:25:00.000000000    3  25  0,50        3,5
2 17:00      20:42      +000000000 03:42:00.000000000    3  42  0,75       3,75
3 17:00      20:06      +000000000 03:06:00.000000000    3   6  0,00          3
4 17:00      20:57      +000000000 03:57:00.000000000    3  57  1,00          4
SQL&gt;

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  • 本文由 发表于 2023年3月8日 14:58:35
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