英文:
In reactJS how to wait for one api call to execute and then call next api
问题
在ReactJS中，如何等待一个API调用执行完毕，然后再调用下一个API。
在我的componentDidMount生命周期方法中，我正在检查数据长度。一旦长度超过4，在这种情况下，我首先想保存数据，然后再检索数据。
componentDidMount = () => {
try {
MyApi.getInstance()
.count()
.then(async (data: any) => {
await this.saveDefaultData(); // await is not working
this.getData();
});
} catch (error) {}
}
saveDefaultData = () => {
try {
MyApi.getInstance().saveSystemDefault();
} catch (error) {}
};
getData = () => {
try {
MyApi.getInstance()
.getAllData()
.then((data: any) => {
// 状态更新操作
})
.catch();
} catch (error) {
// 错误处理
}
};
但是两个调用都是并行执行的，如何使它们按顺序执行。
英文:
In reactJS how to wait for one api call to execute and then call next api.
In my componentDidMount I am checking data length. Once the length is more than 4 in that case first I want to save and then I want to retrieve.
componentDidMount = () => {
try {
MyApi.getInstance()
.count()
.then(async (data: any) => {
await this.saveDefaultData(); // await is not working
this.getData();
});
} catch (error) {}
}
this.saveDefaultData = () => {
try {
MyApi.getInstance().saveSystemDefault();
} catch (error) {}
};
this.getData = () => {
try {
MyApi.getInstance()
.getAllData()
.then((data: any) => {
// state update operation
.catch();
} catch (error) {
Error handling
}
});
};
But both the call is going parlay how to make it sequentially.
答案1
得分: 1
await 不起作用是因为没有声明返回值，因此没有承诺可供 await。如果将 saveDefaultData 函数更改为 return MyApi.getInstance().saveSystemDefault();，它将等待承诺解析。异步函数需要返回值才能正确等待。
英文:
The await is not working because no return value is being declared so it has no promise to await if you change your saveDefaultData function to return MyApi.getInstance().saveSystemDefault(); it will wait for the promise to resolve. Async functions need a return value to be awaited properly
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