英文:
deque::end results in assertion failure
问题
以下是翻译好的部分：
"I was coding some code which needs a deque of structs. Only after 300 lines of repeatedly debugged code and excessive over-engineering, I found out that using the deque::end function somehow doesn't work in this code."
"我正在编写一些需要使用结构体deque的代码。只有在经过了300行不断调试和过度工程化的代码之后，我才发现在这个代码中使用deque::end函数似乎不起作用。"
"any idea on how to solve the issue?"
"有没有解决这个问题的想法？"
"I wanted to create a code which contains a deque of structs, however, an error occurred when I used the function deque::end on the program."
"我想创建一个包含结构体deque的代码，但是在程序中使用deque::end函数时出现了错误。"
英文:
I was coding some code which needs a deque of structs. Only after 300 lines of repeatedly debugged code and excessive over-engineering, I found out that using the deque::end function somehow doesn't work in this code.
Below is a simplified version of the code:
vvv code vvv
#include <iostream>
#include <deque>
#define lli signed long long int
using namespace std;
typedef struct cityData
{
lli height;
lli index;
} cityData;
int main()
{
deque<cityData> city;
lli cityCount;
cin >> cityCount;
for (lli i = 1; i <= cityCount; i++)
{
cityData input;
cin >> input.height;
input.index = i;
city.push_back(input);
}
cout << "firstIndex: " << city.begin()->index << endl;
cout << "lastIndex: " << city.end()->index << endl;
}
vvv Input vvv
10
9 2 8 3 7 2 8 2 9 1
vvv Output vvv
firstIndex: 1
error: cannot dereference out of range deque iterator
code terminated with exit code 3.
any idea on how to solve the issue?
I wanted to create a code which contains a deque of structs, however, an error occured when I used the function deque::end on the program.
答案1
得分: 2
deque::end() 返回指向最后一个元素之后的迭代器，不能被解引用。
你可以使用 deque::back() 来引用最后一个元素。（它返回一个元素的引用，而不是一个迭代器）
英文:
deque::end() returns an iterator to an element past the last element, and it mustn't be dereferenced.
You can use deque::back() to refer to the last element. (This returns a reference to an element, not an iterator)
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