英文:
How to make this subquery not check for null?
问题
我需要一个返回唯一人员的脚本。
"CPF"标识是唯一的值，但这些数据并不总是被记录。所以我希望这个子查询不要比较空值。稍后我会通过姓名进行验证。
我已经有这个查询，但我希望它不比较空值。
SELECT*
FROM TAB.ORIGEM
WHERE NOT EXISTS
(
SELECT 1 FROM TAB.DESTINO
WHERE TAB.DESTINO.CPF = TAB.ORIGEM.CPF
)
下面是表格和我期望的结果的示例。
TAB.ORIGEM
| NAME | CPF |
| -------- | -------- |
| JOAO | 123 |
| MARIA | 321 |
| PAULO | |
TAB.DESTINO
| NAME | CPF |
| -------- | -------- |
| JOAO | 123 |
| JOANA | 456 |
| JOSE | |
RESULT
| NAME | CPF |
| -------- | -------- |
| MARIA | 321 |
| PAULO | |
英文:
I need a script that returns me unique people.
"CPF" identifiers are unique values, but these data are not always registered. so I would like this subquery not to compare null values. And later I will do the verification by name.
I already have this query, but I need it not to compare null values.
SELECT*
FROM TAB.ORIGEM
WHERE NOT EXISTS
(
SELECT 1 FROM TAB.DESTINO
WHERE TAB.DESTINO.CPF = TAB.ORIGEM.CPF
)
Below is an example of the tables and the result I expect.
TAB.ORIGEM
| NAME | CPF |
|---|---|
| JOAO | 123 |
| MARIA | 321 |
| PAULO |
TAB.DESTINO
| NAME | CPF |
|---|---|
| JOAO | 123 |
| JOANA | 456 |
| JOSE |
RESULT
| NAME | CPF |
|---|---|
| MARIA | 321 |
| PAULO |
答案1
得分: 1
以下是已翻译的内容：
不确定我是否正确理解了您的要求，但我认为您需要类似以下的内容：
select d.*
from destino d
where not exists (
select 1
from origem o
where d.cpf=o.cpf
);
英文:
Not sur whether I got your requirements right, yet I think you need something like below:
select d.*
from destino d
where not exists (
select 1
from origem o
where d.cpf=o.cpf
);
答案2
得分: 0
尝试连接。您想要的结果是：
SELECT ORIGEM.* FROM ORIGEM
LEFT JOIN DESTINO
ON DESTINO.CPF = ORIGEM.CPF
WHERE DESTINO.CPF IS NULL
英文:
Try join. The result you want:
SELECT ORIGEM.* FROM ORIGEM
LEFT JOIN DESTINO
ON DESTINO.CPF = ORIGEM.CPF
WHERE DESTINO.CPF IS NULL
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