英文:
jq exclude key for output
问题
{
"I need to exclude field _class from this output:": "我需要从这个输出中排除字段_class:",
"What I use for get this json": "我用什么来获取这个JSON",
"Result must be just:": "结果应该只是:",
"I tried using |not and del, but that didn't work for me.": "我尝试使用|not和del，但对我没有起作用。"
}
英文:
I need to exclude field _class from this output:
{
"_class": "hudson.model.FreeStyleBuild",
"displayName": "NAME-(#1498)",
"number": 1498
}
What I use for get this json
curl -gn http://<jenkins-site>/job/<build-name>/api/json?tree=builds[displayName,number]&pretty=true | jq -r '.builds[] | select(.displayName | contains("NAME"))'
Result must be just:
{
"displayName": "NAME-(#1498)",
"number": 1498
}
I tried using |not and del, but that didn't work for me.
答案1
得分: 3
你可以使用 del 命令来简单地删除该字段：
… | jq '.builds[] | select(.displayName | contains("NAME")) | del(._class)'
{
"displayName": "NAME-(#1498)",
"number": 1498
}
注意：如果输出为 JSON 格式，-r 标志不起作用。
英文:
You can simply delete that field using del:
… | jq '.builds[] | select(.displayName | contains("NAME")) | del(._class)'
{
"displayName": "NAME-(#1498)",
"number": 1498
}
Note: If you output JSON, the -r flag isn't doing anything.
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