英文:
Why is the first method wrong and the second correct?
问题
#第一种方法（不正确）
two_digit_number = input
number0 = two_digit_number[0]
number1 = two_digit_number[1]
int(number0)
int(number1)
result = number0 + number1
print(result)
#第二种方法（正确）
two_digit_number = input
number0 = two_digit_number[0]
number1 = two_digit_number[1]
result = int(number0) + int(number1)
print(result)
数据类型转换是如何工作的？
英文:
#FIRST METHOD(INCORRECT)
two_digit_number = input
number0 = two_digit_number[0]
number1 = two_digit_number[1]
int(number0)
int(number1)
result = number0 + number1
print(result)
#SECOND METHOD(CORRECT)
two_digit_number = input
number0 = two_digit_number[0]
number1 = two_digit_number[1]
result = int(number0) + int(number1)
print(result)
How does converting data types work?
答案1
得分: 1
在第一种方法中，number0 和 number1 没有正确转换为整数。
是的，您对它们调用了 int() 函数，但变量的类型仍然保持不变。
我认为您可以这样做：
two_digit_number = input
number0 = two_digit_number[0]
number1 = two_digit_number[1]
number0 = int(number0)
number1 = int(number1)
result = number0 + number1
print(result)
英文:
In the first method, number0 and number1 were not transformed into int properly.
yes, you called int() function on them but the variables remained the same type.
I think you could have done it this way:
two_digit_number = input
number0 = two_digit_number[0]
number1 = two_digit_number[1]
number0 = int(number0)
number1 = int(number1)
result = number0 + number1
print(result)
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