Get all values of local variable value outside of function

      soup = BeautifulSoup(filehandle, "html.parser")
      soup = soup.find('ul', class_='listing')
      thdr = soup.find('div', class_='heading')

      if (chk == "n"):
         
      while (thdr != None):
      for thdr in thdr:
         global prod      
         temp = thdr.string
         prod = thdr.string
         print prod

I need to print the value of prod ouside of this function and loop.
This variable prod has multiple values but I am getting only the last value when I print this outside of function even after marking it as global.

You can declare an array on top and append items to it in each iteration. And then, print it once with all the values.

soup = BeautifulSoup(filehandle, "html.parser")
uls = soup.find('ul', class_='listing')
thdr = soup.find('div', class_='heading')
prod_items = []
if (chk == "n"):
    for item in thdr:
        prod = item.string
        prod_items.append(prod)
    print(prod_items)

you can make a list(as others are saying) of prod under your if statement then keep appending it under the for loop and finally you can simply add a print statement after the loop is ended to print out the whole list of prod

you don't need to use global keyword

This is what I'm trying to say:

soup = BeautifulSoup(filehandle, "html.parser")
soup = soup.find('ul', class_='listing')
thdrs = soup.find_all('div', class_='heading') 

if chk == "n":
    prods = [] 
    for thdr in thdrs: 
        prod = thdr.string
        prods.append(prod) 
        print(prod) 
    print(prods) 

I'm not quite sure what the code in your question is doing, so I'll use the sample code below to answer your question.

Solution

Using yield keyword. It is used to create a generator function. A type of function that is memory efficient and can be used like an iterator object.

Sample Code

def foo(num):
    while num < 10:
        num += 1
        yield num

for n in foo(0):
    print(n)

Output

1
2
3
4
5
6
7
8
9
10