如何将另一个数组中的字符串附加到Pandas数据框的列?

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英文:

How to append strings to the column of a Dataframe from another array in Pandas?

问题

我有一个类似下面的数据框:

                    ip  metric
0       10.10.20.9       0
1       10.10.1.25       0
2       10.1.13.45       0
3     10.1.100.101       0
4      10.1.100.11       0
5      10.11.2.100       0
6       10.1.2.151       0
7       10.1.2.184       0
8      10.1.20.185       0

我想要将从数组中选取的字符串附加到“ip”列,就像这样:

arr = ["(0)", "(1)", "(2)", "(3)", "(4)", "(5)", "(6)", "(7)", "(8)"]

                    ip  metric
0    10.10.20.9(0)       0
1    10.10.1.25(1)       0
2    10.1.13.45(2)       0
3  10.1.100.101(3)       0
4   10.1.100.11(4)       0
5   10.11.2.100(5)       0
6    10.1.2.151(6)       0
7    10.1.2.184(7)       0
8   10.1.20.185(8)       0

你可以看到我从数组中取出了项目并添加到“ip”列的值中。

现在我知道如何将字符串添加到数据框的列中,可以像下面这样做:

df["ip"] = df["ip"].astype(str) + '%'

但我无法弄清楚如何将数组中的项目添加到数据框列中。有什么方法可以做到这一点吗?

英文:

I have a Dataframe that looks like below

                ip  metric
0       10.10.20.9       0
1       10.10.1.25       0
2       10.1.13.45       0
3     10.1.100.101       0
4      10.1.100.11       0
5      10.11.2.100       0
6       10.1.2.151       0
7       10.1.2.184       0
8      10.1.20.185       0

I want to append some strings to the ip column picked from an array like so

arr = ["(0)", "(1)", "(2)", "(3)", "(4)", "(5)", "(6)", "(7)", "(8)"]

                ip  metric
0    10.10.20.9(0)       0
1    10.10.1.25(1)       0
2    10.1.13.45(2)       0
3  10.1.100.101(3)       0
4   10.1.100.11(4)       0
5   10.11.2.100(5)       0
6    10.1.2.151(6)       0
7    10.1.2.184(7)       0
8   10.1.20.185(8)       0

You can see I took items from the array and added to the values of the ip column.

Now I know how to add a string to the column of a Dataframe by doing something like below

df["ip"] = df["ip"].astype(str) + '%'

But I can't figure out how to add items from an array to the Dataframe column. Any idea how this can be done?

答案1

得分: 3

如你的数组与你的DataFrame长度相同,你可以拼接字符串:

df['ip'] += arr
print(df)

# 输出
                ip  metric
0    10.10.20.9(0)       0
1    10.10.1.25(1)       0
2    10.1.13.45(2)       0
3  10.1.100.101(3)       0
4   10.1.100.11(4)       0
5   10.11.2.100(5)       0
6    10.1.2.151(6)       0
7    10.1.2.184(7)       0
8   10.1.20.185(8)       0
英文:

As your array has the same length of your DataFrame, you can concatenate strings:

df['ip'] += arr
print(df)

# Output
                ip  metric
0    10.10.20.9(0)       0
1    10.10.1.25(1)       0
2    10.1.13.45(2)       0
3  10.1.100.101(3)       0
4   10.1.100.11(4)       0
5   10.11.2.100(5)       0
6    10.1.2.151(6)       0
7    10.1.2.184(7)       0
8   10.1.20.185(8)       0

答案2

得分: -1

尝试使用lambda函数

df['ip'] = df['ip'].apply(lambda x: str(x) + "%")
英文:

Try using a lambda function

df['ip'] = df['ip'].apply(lambda x: str(x) + "%")

huangapple
  • 本文由 发表于 2023年3月7日 13:21:27
  • 转载请务必保留本文链接:https://go.coder-hub.com/75658285.html
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