英文:
How to append strings to the column of a Dataframe from another array in Pandas?
问题
我有一个类似下面的数据框:
ip metric
0 10.10.20.9 0
1 10.10.1.25 0
2 10.1.13.45 0
3 10.1.100.101 0
4 10.1.100.11 0
5 10.11.2.100 0
6 10.1.2.151 0
7 10.1.2.184 0
8 10.1.20.185 0
我想要将从数组中选取的字符串附加到“ip”列,就像这样:
arr = ["(0)", "(1)", "(2)", "(3)", "(4)", "(5)", "(6)", "(7)", "(8)"]
ip metric
0 10.10.20.9(0) 0
1 10.10.1.25(1) 0
2 10.1.13.45(2) 0
3 10.1.100.101(3) 0
4 10.1.100.11(4) 0
5 10.11.2.100(5) 0
6 10.1.2.151(6) 0
7 10.1.2.184(7) 0
8 10.1.20.185(8) 0
你可以看到我从数组中取出了项目并添加到“ip”列的值中。
现在我知道如何将字符串添加到数据框的列中,可以像下面这样做:
df["ip"] = df["ip"].astype(str) + '%'
但我无法弄清楚如何将数组中的项目添加到数据框列中。有什么方法可以做到这一点吗?
英文:
I have a Dataframe that looks like below
ip metric
0 10.10.20.9 0
1 10.10.1.25 0
2 10.1.13.45 0
3 10.1.100.101 0
4 10.1.100.11 0
5 10.11.2.100 0
6 10.1.2.151 0
7 10.1.2.184 0
8 10.1.20.185 0
I want to append some strings to the ip
column picked from an array like so
arr = ["(0)", "(1)", "(2)", "(3)", "(4)", "(5)", "(6)", "(7)", "(8)"]
ip metric
0 10.10.20.9(0) 0
1 10.10.1.25(1) 0
2 10.1.13.45(2) 0
3 10.1.100.101(3) 0
4 10.1.100.11(4) 0
5 10.11.2.100(5) 0
6 10.1.2.151(6) 0
7 10.1.2.184(7) 0
8 10.1.20.185(8) 0
You can see I took items from the array and added to the values of the ip
column.
Now I know how to add a string to the column of a Dataframe by doing something like below
df["ip"] = df["ip"].astype(str) + '%'
But I can't figure out how to add items from an array to the Dataframe column. Any idea how this can be done?
答案1
得分: 3
如你的数组与你的DataFrame长度相同,你可以拼接字符串:
df['ip'] += arr
print(df)
# 输出
ip metric
0 10.10.20.9(0) 0
1 10.10.1.25(1) 0
2 10.1.13.45(2) 0
3 10.1.100.101(3) 0
4 10.1.100.11(4) 0
5 10.11.2.100(5) 0
6 10.1.2.151(6) 0
7 10.1.2.184(7) 0
8 10.1.20.185(8) 0
英文:
As your array has the same length of your DataFrame, you can concatenate strings:
df['ip'] += arr
print(df)
# Output
ip metric
0 10.10.20.9(0) 0
1 10.10.1.25(1) 0
2 10.1.13.45(2) 0
3 10.1.100.101(3) 0
4 10.1.100.11(4) 0
5 10.11.2.100(5) 0
6 10.1.2.151(6) 0
7 10.1.2.184(7) 0
8 10.1.20.185(8) 0
答案2
得分: -1
尝试使用lambda函数
df['ip'] = df['ip'].apply(lambda x: str(x) + "%")
英文:
Try using a lambda function
df['ip'] = df['ip'].apply(lambda x: str(x) + "%")
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