如何在Trino/Presto中筛选出地图中的特定键?

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英文:

How to filter out certain keys in a map in Trino/Presto?

问题

我有一列,其中每一行都是一个包含键值对的地图,我想要过滤掉一些我不关心的键,以便每一行的结果地图是一个经过过滤的版本。

我关心的键将在一个数组中,并且应该进行排序。我该如何使用这个键的数组以及IN运算符,以便我可以使用map_filter函数,或者是否有其他方法来获取每一行的地图,也许可以使用element_at函数。我在文档中没有找到任何相关信息。

到目前为止,我有以下SQL查询:

WITH temp AS (
    SELECT array_sort(filter(map_keys(mapColumn), x -> x not in ('id', 'image')) as myFiltered 
    FROM myTable WHERE myFilter = 'a'
)     
SELECT map_filter(mapColumn, (k, v) -> k in temp.myFiltered) from myTable WHERE myFilter = 'a'

注意:我只提供了SQL查询的翻译,不包括代码部分。

英文:

I have a column which is a map with key value pairs per row and i would like to filter out some keys that I do not care about such that the resultant map is a filtered version per row.

The keys that I care about will be in an array though which should be sorted. How can I use that array of keys along with an IN operator so I can use map_filter function or is there any other way to fetch the map per row using perhaps element_at function. I did not find anything in the documentation.

So far I have this SQL query:

    WITH temp AS (
    SELECT array_sort(filter(map_keys(mapColumn), x -> x not in ('id', 'image')))) as myFiltered 
FROM myTable WHERE myFilter = 'a'
    )     
    SELECT map_filter(mapColumn,(k, v) -> k in temp.myFiltered))) from myTable WHERE myFilter = 'a'

答案1

得分: 0

如果我正确理解您的要求 - 您需要使用 contains 数组函数:

select map_filter(m, (k, v) -> contains(array[1], k)) filtered
from (values (map(array[2,1], array['b', 'a']))) as t(m);

输出:

 filtered
----------
 {1=a}

或者,如果您需要筛选掉某些键 - 那么使用 not contains

select map_filter(m, (k, v) -> not contains(array[1], k)) filtered
from (values (map(array[2,1], array['b', 'a']))) as t(m);

输出:

 filtered
----------
 {2=b}
英文:

If I understood your requirement correctly - you need to use contains array function:

select map_filter(m, (k, v) -> contains(array[1], k)) filtered
from (values (map(array[2,1], array['b', 'a']))) as t(m);

Output:

 filtered
----------
 {1=a}

Or if you need to filter out some keys - then not contains:

select map_filter(m, (k, v) -> not contains(array[1], k)) filtered
from (values (map(array[2,1], array['b', 'a']))) as t(m);

Output:

 filtered
----------
 {2=b}

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  • 本文由 发表于 2023年3月7日 12:58:26
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