使用KQL添加最后一行,以显示基于列值的总计。

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英文:

Adding a last row using KQL to show grand total based on column values

问题

我有以下格式的数据

    let T = datatable(OperationName:string, Result:string)
    [
       "Method1" , "success",
       "Method1" , "failure",
       "Method1" , "success",
       "Method1" , "success",
       "Method1" , "success",
       "Method1" , "failure",
       "Method2" , "success",
       "Method2" , "failure",
       "Method2" , "failure",
    ];
    T 
    | summarize success = countif(Result == "success")
               ,failure = countif(Result == "failure")
               ,total   = count()
                by OperationName

它显示了每种方法的成功和失败次数,以及总数。

是否可以计算一个总和值,即总列值的和,并在最后一行的末尾显示,如下所示?
英文:

I have data in following format

let T = datatable(OperationName:string, Result:string)
[
   "Method1" , "success",
   "Method1" , "failure",
   "Method1" , "success",
   "Method1" , "success",
   "Method1" , "success",
   "Method1" , "failure",
   "Method2" , "success",
   "Method2" , "failure",
   "Method2" , "failure",
];
T 
| summarize success = countif(Result == "success")
           ,failure = countif(Result == "failure")
           ,total   = count()
            by OperationName

Which displays the number of successes and failures per method along with the total.

使用KQL添加最后一行,以显示基于列值的总计。

Is it possible to calculate a grand total value, which is the sum of the total column values, and display it at the end of the last row, as shown below?

使用KQL添加最后一行,以显示基于列值的总计。

答案1

得分: 1

你可以尝试使用 union 与一个已聚合的表格进行合并。

例如:

let T = datatable(OperationName: string, Result: string)
[
    "Method1", "success",
    "Method1", "failure",
    "Method1", "success",
    "Method1", "success",
    "Method1", "success",
    "Method1", "failure",
    "Method2", "success",
    "Method2", "failure",
    "Method2", "failure",
];
T 
| summarize
    success = countif(Result == "success"),
    failure = countif(Result == "failure"),
    total   = count()
 by OperationName
| as hint.materialized=true T
| union (T | summarize success = sum(success), failure = sum(failure), total = sum(total) by OperationName = "Grand Total")
OperationName success failure total
Method2 1 2 3
Method1 4 2 6
Grand Total 5 4 9

或者,如果您对不太直观和不太结构化的输出(出于您自己的原因)感兴趣:

let T = datatable(OperationName: string, Result: string)
[
    "Method1", "success",
    "Method1", "failure",
    "Method1", "success",
    "Method1", "success",
    "Method1", "success",
    "Method1", "failure",
    "Method2", "success",
    "Method2", "failure",
    "Method2", "failure",
];
T 
| summarize
    success = countif(Result == "success"),
    failure = countif(Result == "failure"),
    total   = count()
 by OperationName
| as hint.materialized=true T
| union (T | summarize total = sum(total) by OperationName = "")
| extend total = case(isempty(OperationName), strcat("Grand Total = ", total), tostring(total))
OperationName success failure total
Method2 1 2 3
Method1 4 2 6
Grand Total = 9
英文:

you could try unioning with a row that is an aggregation of the aggregated table.

for example:

let T = datatable(OperationName: string, Result: string)
[
    "Method1", "success",
    "Method1", "failure",
    "Method1", "success",
    "Method1", "success",
    "Method1", "success",
    "Method1", "failure",
    "Method2", "success",
    "Method2", "failure",
    "Method2", "failure",
];
T 
| summarize
    success = countif(Result == "success"),
    failure = countif(Result == "failure"),
    total   = count()
 by OperationName
| as hint.materialized=true T
| union (T | summarize success = sum(success), failure = sum(failure), total = sum(total) by OperationName = "Grand Total")
OperationName success failure total
Method2 1 2 3
Method1 4 2 6
Grand Total 5 4 9

or, if you're interested in a less-intuitive and less-structured output (for reasons of your own):

let T = datatable(OperationName: string, Result: string)
[
    "Method1", "success",
    "Method1", "failure",
    "Method1", "success",
    "Method1", "success",
    "Method1", "success",
    "Method1", "failure",
    "Method2", "success",
    "Method2", "failure",
    "Method2", "failure",
];
T 
| summarize
    success = countif(Result == "success"),
    failure = countif(Result == "failure"),
    total   = count()
 by OperationName
| as hint.materialized=true T
| union (T | summarize total = sum(total) by OperationName = "")
| extend total = case(isempty(OperationName), strcat("Grand Total = ", total), tostring(total))
OperationName success failure total
Method2 1 2 3
Method1 4 2 6
Grand Total = 9

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  • 本文由 发表于 2023年3月7日 12:34:08
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