英文:
Sympy yields `TypeError: unsupported operand type(s) for *: 'interval' and 'complex'` for complex rational expression
问题
以下是您要翻译的代码部分：
from sympy import *
from sympy.plotting import plot_implicit
x, y = symbols('x y', real=True)
alpha = sqrt(2) / 2
expr = 1 + ((1-alpha) * x + y*I) / (1 - alpha * (x + y*I))**2
expr = Eq(abs(expr), 1)
p1 = plot_implicit(expr)
希望这能帮助您解决代码问题。如果您有其他问题，请随时提出。
英文:
I have this sympy script:
from sympy import *
from sympy.plotting import plot_implicit
x, y = symbols('x y', real=True)
alpha = sqrt(2) / 2
expr = 1 + ((1-alpha) * x + y*I) / (1 - alpha * (x + y*I))**2
expr = Eq(abs(expr), 1)
p1 = plot_implicit(expr)
Which is trying to solve R(z) = 1 where:
As far as I can tell the expression I am giving it is correct. Why am I getting incompatible types? Note that if I get rid of the denominator I do get a plot.
Full error:
Traceback (most recent call last):
File "/home/makogan/Documents/University/Math521/A3/A5.py", line 49, in <module>
p1 = plot_implicit(expr)
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/plot_implicit.py", line 430, in plot_implicit
p.show()
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/plot.py", line 240, in show
self._backend.show()
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/plot.py", line 1533, in show
self.process_series()
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/plot.py", line 1530, in process_series
self._process_series(series, ax, parent)
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/plot.py", line 1398, in _process_series
points = s.get_raster()
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/plot_implicit.py", line 87, in get_raster
func(xinterval, yinterval)
File "/home/makogan/.local/lib/python3.10/site-packages/sympy/plotting/experimental_lambdify.py", line 272, in __call__
return self.lambda_func(*args, **kwargs)
File "<string>", line 1, in <lambda>
TypeError: unsupported operand type(s) for *: 'interval' and 'complex'
答案1
得分: 1
这是代码部分，无需翻译。
英文:
That's caused by the fact that sympy's plotting module is using an old and obsolete evaluation module. If you try this new plotting module you'll get the answer:
from sympy import *
from spb import *
var("x:z")
x, y = symbols('x y', real=True)
alpha = sqrt(2) / 2
expr = 1 + ((1 - alpha) * z) / (1 - alpha * z)**2
expr = expr.subs(z, x + I*y)
expr = Eq(abs(expr), 1)
p1 = plot_implicit(expr, x)
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