合并JSON对象的方法

huangapple
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英文:

a way to combine/merge objects in json

问题

我有这种不方便的数据输出，如下所示：

  1. [
  2.     {
  3.         "object_a": {
  4.             "1": "some value of 1",
  5.             "2": "some value of 2",
  6.             "3": ""
  7.         },
  8.         "obejct_b": {
  9.             "1": "",
  10.             "2": "",
  11.             "3": "some value of 3"
  12.         },
  13.         ..一些其他对象..
  14.     }
  15.     {
  16.         "object_a": {
  17.             "1": "some value of 1",
  18.             "2": "",
  19.             "3": "some value of 3"
  20.     },
  21.     "obejct_b": {
  22.         "1": "",
  23.         "2": "some value of 2",
  24.         "3": ""
  25.     },
  26.     ..一些其他对象..
  27.     }
  28.     {
  29.         "object_a": {
  30.             "1": "",
  31.             "2": "some value of 2",
  32.             "3": ""
  33.         },
  34.         "obejct_b": {
  35.             "3": "some value of 3",
  36.             "1": "some value of 1",
  37.             "2": ""
  38.         },
  39.         ..一些其他对象..
  40.     }
  41. ]

我不知道还要添加什么。它看起来就像它现在这样。不幸的是，我无法更改输出格式。问题在于一些数据在"object_a"中，一些在"object_b"中。

期望的输出应该是这样的：

  1. [
  2.     {
  3.         "object": {
  4.             "1": "some value of 1",
  5.             "2": "some value of 2",
  6.             "3": "some value of 3"
  7.         }
  8.         ..一些其他对象..
  9.     }
  10.     {
  11.         "object": {
  12.             "1": "some value of 1",
  13.             "2": "some value of 2",
  14.             "3": "some value of 3"
  15.         }
  16.         ..一些其他对象..
  17.     }
  18.     {
  19.         "object": {
  20.             "2": "some value of 2",
  21.             "3": "some value of 3",
  22.             "1": "some value of 1"
  23.         }
  24.         ..一些其他对象..
  25.     }
  26. ]

我找不到一种使用jQuery来合并两个对象的方法。

英文:

I have this inconvenient output of data, like this:

  1. [
  2.     {
  3.         "object_a": {
  4.             "1": "some value of 1",
  5.             "2": "some value of 2",
  6.             "3": ""
  7.         },
  8.         "obejct_b": {
  9.             "1": "",
  10.             "2": "",
  11.             "3": "some value of 3"
  12.         },
  13.         ..some other objects..
  14.     }
  15.     {
  16.         "object_a": {
  17.             "1": "some value of 1",
  18.             "2": "",
  19.             "3": "some value of 3"
  20.     },
  21.         "obejct_b": {
  22.             "1": "",
  23.             "2": "some value of 2",
  24.             "3": ""
  25.         },
  26.         ..some other objects..
  27.     }
  28.     {
  29.         "object_a": {
  30.             "1": "",
  31.             "2": "some value of 2",
  32.             "3": ""
  33.         },
  34.         "obejct_b": {
  35.             "3": "some value of 3",
  36.             "1": "some value of 1",
  37.             "2": ""
  38.         },
  39.         ..some other objects..
  40.     }
  41. ]

I don't know what more to add. It looks straightforward as it is.
Unfortunately, I cannot change the output format.
The problem is that some data is in "object_a" and some in "object_b"

The desired output would be like:

  1. [
  2.     {
  3.         "object": {
  4.             "1": "some value of 1",
  5.             "2": "some value of 2",
  6.             "3": "some value of 3"
  7.         }
  8.         ..some other objects..
  9.     }
  10. 	{
  11.         "object": {
  12.             "1": "some value of 1",
  13.             "2": "some value of 2",
  14.             "3": "some value of 3"
  15.         },
  16.         ..some other objects..
  17.     }
  18.         {
  19.         "object": {
  20.             "2": "some value of 2",
  21.             "3": "some value of 3",
  22.             "1": "some value of 1",
  23.         },
  24.         ..some other objects..
  25.     }
  26. ]

I couldn't find a way to combine/merge two objects together, with jQuery.

Thanks.

答案1

得分: 0

以下是翻译好的代码部分，不包含其他内容：

  1. const output = [
  2.   {
  3.     "object_a": {
  4.       "1": "some value of 1",
  5.       "2": "some value of 2",
  6.       "3": ""
  7.     },
  8.     "obejct_b": {
  9.       "1": "",
  10.       "2": "",
  11.       "3": "some value of 3"
  12.     },
  13.     "some other object": {
  14.       "foo": "bar"
  15.     }
  16.   },
  17.   {
  18.     "object_a": {
  19.       "1": "some value of 1",
  20.       "2": "",
  21.       "3": "some value of 3"
  22.     },
  23.     "obejct_b": {
  24.       "1": "",
  25.       "2": "some value of 2",
  26.       "3": ""
  27.     }
  28.   },
  29.   {
  30.     "object_a": {
  31.       "1": "",
  32.       "2": "some value of 2",
  33.       "3": ""
  34.     },
  35.     "obejct_b": {
  36.       "3": "some value of 3",
  37.       "1": "some value of 1",
  38.       "2": ""
  39.     }
  40.   }
  41. ];
  43. const merged = output.map(item => {
  44.   // assumes object_a and obejct_b have the same keys
  45.    const mergedAB =  Object.keys(item.object_a).reduce((acc, key) => {
  46.     // assuming typo in "obejct_b" is intentional
  47.     acc[key] = item.object_a[key] || item.obejct_b[key];
  48.     return acc;
  49.   });
  50.   
  51.   const others = { ...item };
  52.   delete others.object_a;
  53.   delete others.obejct_b;
  54.   
  55.   return {
  56.     object: mergedAB,
  57.     ...others
  58.   }
  59. });
  61. document.body.innerHTML = `<pre>${JSON.stringify(merged, null, 2)}</pre>`;

注意：代码中有一个拼写错误 "obejct_b" 应该是 "object_b"，请根据需要进行更正。

英文:

Some assumptions must be made:

  • Every object in the top-level array will have the same two (and only these two) properties object_a and obejct_b [sic].
  • Every object_a and obejct_b will have the same set of properties.
  • For any key in an object_a that is an empty string, the value in the "merged" result should be that of the corresponding obejct_b.

With these assumptions, I would use the following code.
(Note that I have left as is the typo in obejct_b.)

<!-- begin snippet: js hide: false console: true babel: false -->

<!-- language: lang-js -->

  1. const output = [
  2. {
  3. &quot;object_a&quot;: {
  4. &quot;1&quot;: &quot;some value of 1&quot;,
  5. &quot;2&quot;: &quot;some value of 2&quot;,
  6. &quot;3&quot;: &quot;&quot;
  7. },
  8. &quot;obejct_b&quot;: {
  9. &quot;1&quot;: &quot;&quot;,
  10. &quot;2&quot;: &quot;&quot;,
  11. &quot;3&quot;: &quot;some value of 3&quot;
  12. },
  13. &quot;some other object&quot;: {
  14. &quot;foo&quot; : &quot;bar&quot;
  15. }
  16. },
  17. {
  18. &quot;object_a&quot;: {
  19. &quot;1&quot;: &quot;some value of 1&quot;,
  20. &quot;2&quot;: &quot;&quot;,
  21. &quot;3&quot;: &quot;some value of 3&quot;
  22. },
  23. &quot;obejct_b&quot;: {
  24. &quot;1&quot;: &quot;&quot;,
  25. &quot;2&quot;: &quot;some value of 2&quot;,
  26. &quot;3&quot;: &quot;&quot;
  27. }
  28. },
  29. {
  30. &quot;object_a&quot;: {
  31. &quot;1&quot;: &quot;&quot;,
  32. &quot;2&quot;: &quot;some value of 2&quot;,
  33. &quot;3&quot;: &quot;&quot;
  34. },
  35. &quot;obejct_b&quot;: {
  36. &quot;3&quot;: &quot;some value of 3&quot;,
  37. &quot;1&quot;: &quot;some value of 1&quot;,
  38. &quot;2&quot;: &quot;&quot;
  39. }
  40. }
  41. ];
  42. const merged = output.map(item =&gt; {
  43. // assumes object_a and obejct_b have the same keys
  44. const mergedAB =  Object.keys(item.object_a).reduce((acc, key) =&gt; {
  45. // assuming typo in &quot;obejct_b&quot; is intentional
  46. acc[key] = item.object_a[key] || item.obejct_b[key];
  47. return acc;
  48. }, {});
  49. const others = { ...item };
  50. delete others.object_a;
  51. delete others.obejct_b;
  52. return {
  53. object: mergedAB,
  54. ...others
  55. }
  56. });
  57. document.body.innerHTML = `&lt;pre&gt;${JSON.stringify(merged, null, 2)}&lt;/pre&gt;`;

<!-- end snippet -->

huangapple
  • 本文由 发表于 2023年3月7日 05:02:46
  • 转载请务必保留本文链接：https://go.coder-hub.com/75655822.html
  • jquery
  • json
  • merge
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