英文:
User Input going through list of Dictionaries
问题
我尝试使输出返回先前的列表而不是相同的列表。我创建了两个列表，一个用于每次搜索的新条目，另一个用于保存搜索以便在用户输入为'back'时使用。
string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
a = ['Name', 'Age', 'Food', 'Drink', 'Place']
b = ['Name', 'Age', 'Food', 'Drink']
c = ['Name', 'Age', 'Food']
e = []
f = []
l = []
pre = []
# 根据它们的值的数量将键与值关联起来：
for line in string.splitlines():
words = line.split(' ')
f.append(words)
if (len(words) == 5):
e.append((dict(zip(a, line.split())))
elif (len(words) == 4):
e.append((dict(zip(b, line.split())))
else:
e.append((dict(zip(c, line.split())))
search = input("Enter key: ") # 获取第一个输入
while search != "q": # 如果输入等于q，退出
entry = search.split() # 如果输入了多个键，将搜索分割为列表
if 'back' in entry and len(pre) == 0: # 返回原始数据列表
print('\n', e, '\n')
elif 'back' in entry and len(pre) != 0: # 返回以前的条目
print('\n', pre, '\n')
pre.clear() # 打印后清除以前的条目
else:
pre.clear() # 清除以前的条目
for val in e: # 在列表中查找Name
for word in entry:
if word in val["Name"]:
l.append(val)
pre.append(val)
if len(l) != 0: # 如果输出列表包含内容，请打印它
print('\n', l, '\n')
l.clear() # 为新条目清除
search = input("Enter key: ") # 下一个搜索
else:
print("\ngoodbye. . .") # 如果输入为q，则打印Goodbye
从脚本中我得到：
Enter key: Sam
[{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
Enter key: Joe Mike
[{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
Enter key: back
[{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
我想要的是：
Enter key: Sam
[{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
Enter key: Joe Mike
[{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
Enter key: back
[{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
我认为这与如何保存以前的条目有关，但不确定如何返回它。任何有助于引导我到正确方法的帮助都将有所帮助。
英文:
I am trying to have the output to return the previous list instead of the same list. I created two lists, one for the new entry for every search and one to save the search to be used if the User input is 'back'.
string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
a = ['Name','Age','Food','Drink','Place']
b = ['Name','Age','Food','Drink']
c = ['Name','Age','Food',]
e =[]
f = []
l = []
pre = []
#Attaching keys with their values based off the number of values(words) they have:
for line in string.splitlines():
words = line.split(' ')
f.append(words)
if (len(words) == 5):
e.append((dict(zip(a, line.split()))))
elif (len(words) == 4):
e.append((dict(zip(b, line.split()))))
else:
e.append((dict(zip(c, line.split()))))
search = input("Enter key: ") # Get first input
while search != "q": # If input equals to q, quit
entry = search.split() # Split the search into a list if multiply keys are inputted
if 'back' in entry and len(pre) == 0 : # return the orginal data list
print('\n',e,'\n')
elif 'back' in entry and len(pre) != 0: # Return previous entry
print('\n',pre,'\n')
pre.clear() # Clear the previous entry after printing
else:
pre.clear() # Clear the previous entry
for val in e: # Look for Name in List
for word in entry:
if word in val["Name"]:
l.append(val)
pre.append(val)
if len(l) != 0: # If the the output list contains something print it
print('\n',l,'\n')
l.clear() # Clear for the new entry
search = input("Enter key: ") # Next Search
else:
print("\ngoodbye. . .") # Print Goodbye if input was q
From my script I get:
Enter key: Sam
[{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
Enter key: Joe Mike
[{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
Enter key: back
[{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
I would like to get
Enter key: Sam
[{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
Enter key: Joe Mike
[{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
Enter key: back
[{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
I believe it has something to do with how I save the previous entry but not sure how to go back it. Any help to lead me to the correct approach would be helpful
答案1
得分: 0
你需要两个变量。一个用于存储最后的结果，另一个用于存储倒数第二的结果。在每次搜索之前，将最后的结果复制到倒数第二的结果。当输入"back"时，打印倒数第二的结果。
string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
keys = ['Name', 'Age', 'Food', 'Drink', 'Place']
e = []
f = []
l = []
pre = []
pre_pre = []
#根据它们拥有的值(单词)的数量，将键与它们的值关联起来：
for line in string.splitlines():
words = line.split()
f.append(words)
e.append(dict(zip(keys, words)))
search = input("Enter key: ") # 获取第一个输入
while search != "q": # 如果输入等于"q"，则退出
entry = search.split() # 如果输入了多个键，将搜索拆分成列表
if 'back' in entry and len(pre_pre) == 0 : # 返回原始数据列表
print('\n', e, '\n')
elif 'back' in entry and len(pre_pre) != 0: # 返回上一个条目
print('\n', pre_pre, '\n')
pre.clear() # 打印后清除上一个条目
else:
pre_pre = pre
pre = [] # 清除上一个条目
for val in e: # 在列表中查找"Name"
for word in entry:
if word in val["Name"]:
l.append(val)
pre.append(val)
if len(l) != 0: # 如果输出列表包含内容，则打印它
print('\n', l, '\n')
l.clear() # 为新的搜索清除
search = input("Enter key: ") # 下一个搜索
else:
print("\ngoodbye. . .") # 如果输入是"q"，则打印"再见"
英文:
You need two variables. One for the last result, another for the 2nd-to-last result. Before each search, copy the last to the 2nd-to-last. When they enter back, print the 2nd-to-last.
string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
keys = ['Name','Age','Food','Drink','Place']
e =[]
f = []
l = []
pre = []
pre_pre = []
#Attaching keys with their values based off the number of values(words) they have:
for line in string.splitlines():
words = line.split()
f.append(words)
e.append(dict(zip(keys, words)))
search = input("Enter key: ") # Get first input
while search != "q": # If input equals to q, quit
entry = search.split() # Split the search into a list if multiply keys are inputted
if 'back' in entry and len(pre_pre) == 0 : # return the orginal data list
print('\n',e,'\n')
elif 'back' in entry and len(pre_pre) != 0: # Return previous entry
print('\n',pre_pre,'\n')
pre.clear() # Clear the previous entry after printing
else:
pre_pre = pre
pre = [] # Clear the previous entry
for val in e: # Look for Name in List
for word in entry:
if word in val["Name"]:
l.append(val)
pre.append(val)
if len(l) != 0: # If the the output list contains something print it
print('\n',l,'\n')
l.clear() # Clear for the new entry
search = input("Enter key: ") # Next Search
else:
print("\ngoodbye. . .") # Print Goodbye if input was q
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