用户输入经过字典列表。

huangapple
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英文:

User Input going through list of Dictionaries

问题

我尝试使输出返回先前的列表而不是相同的列表。我创建了两个列表，一个用于每次搜索的新条目，另一个用于保存搜索以便在用户输入为'back'时使用。

  1. string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
  3. a = ['Name', 'Age', 'Food', 'Drink', 'Place']
  4. b = ['Name', 'Age', 'Food', 'Drink']
  5. c = ['Name', 'Age', 'Food']
  7. e = []
  8. f = []
  9. l = []
  10. pre = []
  12. # 根据它们的值的数量将键与值关联起来：
  13. for line in string.splitlines():
  14.     words = line.split(' ')
  15.     f.append(words)
  16.     if (len(words) == 5):
  17.         e.append((dict(zip(a, line.split())))
  18.     elif (len(words) == 4):
  19.         e.append((dict(zip(b, line.split())))
  20.     else:
  21.         e.append((dict(zip(c, line.split())))
  23. search = input("Enter key: ")  # 获取第一个输入
  24. while search != "q":  # 如果输入等于q，退出
  25.     entry = search.split()  # 如果输入了多个键，将搜索分割为列表
  26.     if 'back' in entry and len(pre) == 0:  # 返回原始数据列表
  27.         print('\n', e, '\n')
  28.     elif 'back' in entry and len(pre) != 0:  # 返回以前的条目
  29.         print('\n', pre, '\n')
  30.         pre.clear()  # 打印后清除以前的条目
  31.     else:
  32.         pre.clear()  # 清除以前的条目
  33.         for val in e:  # 在列表中查找Name
  34.             for word in entry:
  35.                 if word in val["Name"]:
  36.                     l.append(val)
  37.                     pre.append(val)
  38.     if len(l) != 0:  # 如果输出列表包含内容，请打印它
  39.         print('\n', l, '\n')
  41.     l.clear()  # 为新条目清除
  42.     search = input("Enter key: ")  # 下一个搜索
  43. else:
  44.     print("\ngoodbye. . .")  # 如果输入为q，则打印Goodbye

从脚本中我得到：

  1. Enter key: Sam
  3. [{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
  5. Enter key: Joe Mike
  7. [{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
  9. Enter key: back
  11. [{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]

我想要的是：

  1. Enter key: Sam
  3. [{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]
  5. Enter key: Joe Mike
  7. [{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]
  9. Enter key: back
  11. [{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]

我认为这与如何保存以前的条目有关，但不确定如何返回它。任何有助于引导我到正确方法的帮助都将有所帮助。

英文:

I am trying to have the output to return the previous list instead of the same list. I created two lists, one for the new entry for every search and one to save the search to be used if the User input is 'back'.

  1. string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
  4. a = ['Name','Age','Food','Drink','Place']
  5. b = ['Name','Age','Food','Drink']
  6. c = ['Name','Age','Food',]
  8. e =[]
  9. f = []
  10. l = []   
  11. pre = []   
  13. #Attaching keys with their values based off the number of values(words) they have:
  14. for line in string.splitlines():
  15.     words = line.split(' ')
  16.     f.append(words)
  17.     if (len(words) == 5):
  18.        e.append((dict(zip(a, line.split()))))
  19.     elif (len(words) == 4):
  20.          e.append((dict(zip(b, line.split()))))
  21.     else:
  22.            e.append((dict(zip(c, line.split()))))
  23.     
  24. search = input("Enter key: ")       # Get first input
  25. while search != "q":                # If input equals to q, quit
  26.     entry = search.split()          # Split the search into a list if multiply keys are inputted
  27.     if 'back' in entry and len(pre) == 0 :   # return the orginal data list
  28.         print('\n',e,'\n')                  
  30.     elif 'back' in entry and len(pre) != 0:     # Return previous entry
  31.         print('\n',pre,'\n')
  32.         pre.clear()                             # Clear the previous entry after printing 
  33.     else:
  34.         pre.clear()                             # Clear the previous entry
  35.         for val in e:                           # Look for Name in List
  36.             for word in entry:
  37.                 if word in val["Name"]:
  38.                         l.append(val)
  39.                         pre.append(val)
  40.     if len(l) != 0:                             # If the the output list contains something print it
  41.         print('\n',l,'\n')
  43.     l.clear()                                   # Clear for the new entry
  44.     search = input("Enter key: ")               # Next Search
  45. else:
  46.    print("\ngoodbye. . .")                      # Print Goodbye if input was q
  47.

From my script I get:

  1. Enter key: Sam
  3.  [{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}] 
  5. Enter key: Joe Mike
  7.  [{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}] 
  9. Enter key: back
  11.  [{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}]

I would like to get

  1. Enter key: Sam
  3.  [{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}] 
  5. Enter key: Joe Mike
  7.  [{'Name': 'Joe', 'Age': '19', 'Food': 'hamburger', 'Drink': 'sprite'}, {'Name': 'Mike', 'Age': '25', 'Food': 'cake', 'Drink': 'fanta', 'Place': 'museum'}] 
  9. Enter key: back
  11.  [{'Name': 'Sam', 'Age': '23', 'Food': 'pizza', 'Drink': 'cola', 'Place': 'park'}]

I believe it has something to do with how I save the previous entry but not sure how to go back it. Any help to lead me to the correct approach would be helpful

答案1

得分: 0

你需要两个变量。一个用于存储最后的结果，另一个用于存储倒数第二的结果。在每次搜索之前，将最后的结果复制到倒数第二的结果。当输入"back"时，打印倒数第二的结果。

  1. string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
  3. keys = ['Name', 'Age', 'Food', 'Drink', 'Place']
  5. e = []
  6. f = []
  7. l = []
  8. pre = []
  9. pre_pre = []
  11. #根据它们拥有的值(单词)的数量，将键与它们的值关联起来：
  12. for line in string.splitlines():
  13.     words = line.split()
  14.     f.append(words)
  15.     e.append(dict(zip(keys, words)))
  17. search = input("Enter key: ")       # 获取第一个输入
  18. while search != "q":                # 如果输入等于"q"，则退出
  19.     entry = search.split()          # 如果输入了多个键，将搜索拆分成列表
  20.     if 'back' in entry and len(pre_pre) == 0 :   # 返回原始数据列表
  21.         print('\n', e, '\n')
  23.     elif 'back' in entry and len(pre_pre) != 0:     # 返回上一个条目
  24.         print('\n', pre_pre, '\n')
  25.         pre.clear()                             # 打印后清除上一个条目
  26.     else:
  27.         pre_pre = pre
  28.         pre = []                             # 清除上一个条目
  29.         for val in e:                           # 在列表中查找"Name"
  30.             for word in entry:
  31.                 if word in val["Name"]:
  32.                         l.append(val)
  33.                         pre.append(val)
  34.     if len(l) != 0:                             # 如果输出列表包含内容，则打印它
  35.         print('\n', l, '\n')
  37.     l.clear()                                   # 为新的搜索清除
  38.     search = input("Enter key: ")               # 下一个搜索
  39. else:
  40.    print("\ngoodbye. . .")                      # 如果输入是"q"，则打印"再见"
英文:

You need two variables. One for the last result, another for the 2nd-to-last result. Before each search, copy the last to the 2nd-to-last. When they enter back, print the 2nd-to-last.

  1. string = "Sam 23 pizza cola park\nJoe 19 hamburger sprite\nMike 25 cake fanta museum\nBen 22 pie"
  3. keys = ['Name','Age','Food','Drink','Place']
  5. e =[]
  6. f = []
  7. l = []
  8. pre = []
  9. pre_pre = []
  11. #Attaching keys with their values based off the number of values(words) they have:
  12. for line in string.splitlines():
  13.     words = line.split()
  14.     f.append(words)
  15.     e.append(dict(zip(keys, words)))
  17. search = input("Enter key: ")       # Get first input
  18. while search != "q":                # If input equals to q, quit
  19.     entry = search.split()          # Split the search into a list if multiply keys are inputted
  20.     if 'back' in entry and len(pre_pre) == 0 :   # return the orginal data list
  21.         print('\n',e,'\n')
  23.     elif 'back' in entry and len(pre_pre) != 0:     # Return previous entry
  24.         print('\n',pre_pre,'\n')
  25.         pre.clear()                             # Clear the previous entry after printing
  26.     else:
  27.         pre_pre = pre
  28.         pre = []                             # Clear the previous entry
  29.         for val in e:                           # Look for Name in List
  30.             for word in entry:
  31.                 if word in val["Name"]:
  32.                         l.append(val)
  33.                         pre.append(val)
  34.     if len(l) != 0:                             # If the the output list contains something print it
  35.         print('\n',l,'\n')
  37.     l.clear()                                   # Clear for the new entry
  38.     search = input("Enter key: ")               # Next Search
  39. else:
  40.    print("\ngoodbye. . .")                      # Print Goodbye if input was q

huangapple
  • 本文由 发表于 2023年3月7日 05:02:44
  • 转载请务必保留本文链接：https://go.coder-hub.com/75655820.html
  • dictionary
  • list
  • python
  • user-input
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