英文:
How do you extract the numbers from a text file while also stating the line each appears on? (Python)
问题
I found 55 on line 1
I found 6 on line 1
I found 6 on line 1
I found 6 on line 1
I found 6 on line 1
I found 9 on line 1
I found 9 on line 1
I found 5 on line 2
I found 7 on line 2
I found 6 on line 2
I found 6 on line 2
I found 6 on line 2
I found 4 on line 2
I found 3 on line 2
I found 7 on line 2
I found 8 on line 2
I found 3 on line 2
I found 4 on line 2
I found 9 on line 2
英文:
I need to know how to extract a number from a text file while also having it tell me what line the number is on. But i need it to paste the output to a new text file
Program:
fname = input("Enter file name: ")
with open(fname, 'r') as f:
for line in f:
words = line.split()
for i in words:
for letter in i:
if(letter.isdigit()):
print('I found ',letter)
Text File:
fufge55gf6eh6h6eh6f9hg9hj
vgcg57vgr6vgn66cg4w3vgv78v
gv3c4ghc978c67654cchch
v4bci7r6ec5wgv
Output:
Enter file name: superpleasework.txt
I found 5
I found 5
I found 6
I found 6
I found 6
I found 6
I found 9
I found 9
I found 5
I found 7
I found 6
I found 6
I found 6
I found 4
I found 3
I found 7
I found 8
I found 3
I found 4
I found 9
...etc
I was expecting it to look like this:
I found 55 on line 1
I found 6 on line 1
I found 6 on line 1
I found 6 on line 1
I found 6 on line 1
I found 9 on line 1
I found 9 on line 1...etc
I need it to tell me the line each number is on (without separating the numbers that are together).
答案1
得分: 1
你写了
for line in f:
如果你使用
[enumerate](https://docs.python.org/3/library/functions.html#enumerate)
来包装文件迭代器，你的问题就变得简单了。
for line_num, line in enumerate(f):
...
print('我在第', letter, '行找到了', line_num)
<details>
<summary>英文:</summary>
You wrote
for line in f:
If you wrap that file iterator with
[enumerate](https://docs.python.org/3/library/functions.html#enumerate)
your problem becomes simple.
for line_num, line in enumerate(f):
...
print('I found ', letter, 'on line number', line_num)
</details>
# 答案2
**得分**: 0
你可以使用groupby函数（来自itertools模块）与str.isdigit函数来分离字符序列中交替出现的数字和非数字字符。
要获取行号，可以在for循环中使用enumerate()：
```python
from itertools import groupby
for lineNumber, line in enumerate(f, 1):
numbers = ("".join(digits) for isNum, digits in groupby(line, str.isdigit) if isNum)
for number in numbers:
print("在第", lineNumber, "行找到", number)
输出结果：
在第 1 行找到 55
在第 1 行找到 6
在第 1 行找到 6
在第 1 行找到 6
在第 1 行找到 6
在第 1 行找到 9
在第 1 行找到 9
在第 2 行找到 57
在第 2 行找到 6
在第 2 行找到 66
在第 2 行找到 4
在第 2 行找到 3
在第 2 行找到 78
在第 3 行找到 3
在第 3 行找到 4
在第 3 行找到 978
在第 3 行找到 67654
在第 4 行找到 4
在第 4 行找到 7
在第 4 行找到 6
在第 4 行找到 5
希望这对你有帮助。
英文:
You could use the groupby function (form itertools) with the str.isdigit function to separate the lines on the alternating numeric and non-numeric sequences of characters.
To get the line numbers, use enumerate() in your for-loop:
from itertools import groupby
for lineNumber,line in enumerate(f,1):
numbers = ("".join(digits) for isNum,digits
in groupby(line,str.isdigit) if isNum)
for number in numbers:
print("I found ",number,"on line",lineNumber)
output:
I found 55 on line 1
I found 6 on line 1
I found 6 on line 1
I found 6 on line 1
I found 6 on line 1
I found 9 on line 1
I found 9 on line 1
I found 57 on line 2
I found 6 on line 2
I found 66 on line 2
I found 4 on line 2
I found 3 on line 2
I found 78 on line 2
I found 3 on line 3
I found 4 on line 3
I found 978 on line 3
I found 67654 on line 3
I found 4 on line 4
I found 7 on line 4
I found 6 on line 4
I found 5 on line 4
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