Starting a shell script in a new Terminal using python and get exit code

I'm currently trying to run a shell script via python in a new terminal. So far it is working right now, my issue now is that I also need the exit code of that shell script. Depending on successful execution or not the script returns different exit codes and I need to get them so I can continue working with them in python. My code looks like that right now:

    process = subprocess.Popen(['gnome-terminal', '-x', './myscript.sh'])
    text = process.communicate()[0]
    exit_code = process.returncode
    print(text, exit_code)

I probably also need a wait function, because the script needs few seconds to finish execution. Does anyone know how I can do all that?

As @tjm3772 mentioned in the comments, subprocess.run is probably what you want. e.g.

import subprocess

process = subprocess.run(['bash', './bash_script.sh'], capture_output=True, timeout=120)
text = process.stdout
exit_code = process.returncode
print(text, exit_code)

Both capture_output and timeout are optional. timeout is in seconds. As you'll see from the docs, there are many other options if required.

run returns a CompletedProcess object representing a process that has finished. So no need to worry about (in your Python code) how long your shell script may take etcetera. (Other than perhaps wanting a timeout as mentioned above to cover the possible scenario of your script hanging/taking too long.)