英文:
How to replace word with special character from string in java?
问题
我正在编写一个方法，应该将与列表中的单词匹配的所有单词替换为'****'。
到目前为止，我的代码可以很好地处理没有特殊字符的字符串，但所有带有特殊字符的字符串都会被忽略。
以下是迄今为止我拥有的代码：
public static String maskKeywordData(String data, List<String> keywords) {
for (String keyword: keywords) {
String insensitiveWord = "(?i)\\b" + keyword + "\\b";
data = data.replaceAll(insensitiveWord, StringUtils.repeat("*", keyword.length()));
}
return data;
}
例如，我有一个关键词列表 ['c.u.n.t', 'a$$', 'bitch']。
输入: "Hello c.u.n.t with a$$ and bitch"
期望的输出: "Hello ******* with *** and *****"
英文:
I am writing a method that should replace all words which match with ones from the list with '****'.
So far I have code that works fine with strings without special characters but all string with special characters are ignoring.
Here's the code I have so far:
public static String maskKeywordData(String data, List<String> keywords) {
for (String keyword: keywords) {
String insensitiveWord = "(?i)\\b" + keyword + "\\b";
data = data.replaceAll(insensitiveWord, StringUtils.repeat("*", keyword.length()));
}
return data;
}
E.g. I have a list of keywords ['c.u.n.t', 'a$$', 'bitch'].
Input : "Hello c.u.n.t with a$$ and bitch"
Expected output : "Hello ******* with *** and *****"
答案1
得分: 1
你可以使用以下代码：
public static String maskKeywordData(String data, List<String> keywords) {
for (String keyword : keywords) {
String insensitiveWord = "(?i)\\b" + keyword;
data = data.replaceAll(insensitiveWord, "*".repeat(keyword.length()));
}
return data;
}
它唯一的缺点是，在关键词列表中，对于 $，你必须使用\\$在单词中，例如，a$$ 在列表中必须写成 a\\$\\$ 才能让上述代码运行。
原因是，\\b 表示单词边界，它检查 (^ \w|\w $|\W \w|\w \W)，因此，单词 a$$ 不会被匹配。
以上代码的输出为：
Hello ******* with **** and *****
英文:
You can use
public static String maskKeywordData(String data, List<String> keywords) {
for (String keyword : keywords) {
String insensitiveWord = "(?i)\\b" + keyword;
data = data.replaceAll(insensitiveWord, "*".repeat(keyword.length()));
}
return data;
}
Its only downside is, in the list, for $ you have to use\\$ in the word, like a$$ will be a\\$\\$ in the list for the above code to run.
Reason is, \\b is word boundary which checks for (^ \w|\w $|\W \w|\w \W), due to which the word a$$ is not taken.
Output by the above code:
Hello ******* with **** and *****
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