英文:
How to convert a numeric variable that counts the number of months since a certain point into a variable with an interpretable date (R)?
问题
我有R中的数据，其中有一个数字变量，表示自1960年1月以来的月数。
让我们说：
months_since_1960 <- c(0, 1, 12, 13, 24, 25)
我如何创建一个新的日期变量，以有价值的方式显示这些日期？
我希望得到类似这样的结果：
date <- (1960-01,1960-02,1961-01,1961-02,1962-01,1962-02)
我相信这是一个简单的修复，但我已经尝试过了，似乎无法弄清楚...
英文:
I have data in R that has a numeric variable that counts the number of months since Jan. 1960.
Let’s say:
months_since_1960 <- c(0, 1, 12, 13, 24, 25)
How can I create a new date variable that will show me these dates in a valuable way?
I'm hoping for something like:
date <- (1960-01,1960-02,1961-01,1961-02,1962-01,1962-02)
I'm sure it's an easy fix but I've tried identifying this and I can't seem to figure it out...
答案1
得分: 2
这是什么样子的吗？
library(lubridate)months_since_1960 <- c(0, 1, 12, 13, 24, 25)date_ref = as.Date("1960-01-01")date_ref %m+% months(months_since_1960)
英文:
Is it something like that ?
library(lubridate)months_since_1960 <- c(0, 1, 12, 13, 24, 25)date_ref = as.Date("1960-01-01")date_ref %m+% months(months_since_1960)
答案2
得分: 0
- 创建一个yearmon变量，它内部表示日期，由年份+分数表示，其中分数为0、1/12、…、11/12，代表12个月。然后我们可以使用它或将其转换为Date，从而有多种可能性。
library(zoo)months_since_1960 <- c(0, 1, 12, 13, 24, 25)ym <- as.yearmon(1960) + months_since_1960 / 12ym # 年份和月份## [1] "Jan 1960" "Feb 1960" "Jan 1961" "Feb 1961" "Jan 1962" "Feb 1962"as.Date(ym) # 月初## [1] "1960-01-01" "1960-02-01" "1961-01-01" "1961-02-01" "1962-01-01" "1962-02-01"as.Date(ym, frac = 1) # 月末## [1] "1960-01-31" "1960-02-29" "1961-01-31" "1961-02-28" "1962-01-31" "1962-02-28"
- 使用基本的R（没有包）可以这样获得每月的第一天：
dat <- months_since_1960 |lapply(\(x) tail(seq(as.Date("1960-01-01"), length = x+1, by = "month"), 1)) |do.call(what = "c")dat## [1] "1960-01-01" "1960-02-01" "1961-01-01" "1961-02-01" "1962-01-01" "1962-02-01"或者获取每月的最后一天：```Ras.Date(cut(dat + 31, "month")) - 1## [1] "1960-01-31" "1960-02-29" "1961-01-31" "1961-02-28" "1962-01-31" "1962-02-28"
2a) 或者使用相同的转换来获取月末日期（如果需要的话）：
dat2 <- as.Date(ISOdate(1960 + (months_since_1960 %/% 12), months_since_1960 %% 12 + 1, 1))dat2## [1] "1960-01-01" "1960-02-01" "1961-01-01" "1961-02-01" "1962-01-01" "1962-02-01"
英文:
1) yearmon First create a yearmon variable which internally represents a date by year + fraction where fraction is 0, 1/12, ..., 11/12 for the 12 months. Then we can use that or convert to Date giving several possibilities.
library(zoo)months_since_1960 <- c(0, 1, 12, 13, 24, 25)ym <- as.yearmon(1960) + months_since_1960 / 12ym # year and month## [1] "Jan 1960" "Feb 1960" "Jan 1961" "Feb 1961" "Jan 1962" "Feb 1962"as.Date(ym) # first of month## [1] "1960-01-01" "1960-02-01" "1961-01-01" "1961-02-01" "1962-01-01" "1962-02-01"as.Date(ym, frac = 1) # last of month## [1] "1960-01-31" "1960-02-29" "1961-01-31" "1961-02-28" "1962-01-31" "1962-02-28"
2) Base R With base R (no packages) we can do this to get the first of the month:
dat <- months_since_1960 |>lapply(\(x) tail(seq(as.Date("1960-01-01"), length = x+1, by = "month"), 1)) |>do.call(what = "c")dat## [1] "1960-01-01" "1960-02-01" "1961-01-01" "1961-02-01" "1962-01-01" "1962-02-01"
or for last of of month
as.Date(cut(dat + 31, "month")) - 1## [1] "1960-01-31" "1960-02-29" "1961-01-31" "1961-02-28" "1962-01-31" "1962-02-28"
2a) or this where we can use the same transformation to get end of month if desired:
dat2 <- as.Date(ISOdate(1960 + (months_since_1960 %/% 12), months_since_1960 %% 12 + 1, 1))dat2## [1] "1960-01-01" "1960-02-01" "1961-01-01" "1961-02-01" "1962-01-01" "1962-02-01"
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